How to calculate oxidation number of Iron in ferric ferrocyanide $\text{F}{{\text{e}}_{4}}{{[\text{Fe(CN}{{\text{)}}_{4}}]}_{3}}$?
Answer
566.7k+ views
Hint: Oxidation number or state is an arbitrary number which is present on an element on an element or atom when they are attached in compound.
In a compound various elements are present which can have either positive or negative charge. In any compound, negative charge is present mainly on electronegative atoms while positive charge is present mainly on electropositive atom.
Complete step by step answer:
Given molecule is $\text{F}{{\text{e}}_{4}}{{[\text{Fe(Cn}{{\text{)}}_{6}}]}_{3}}$
Here \[\overset{-}{\mathop{\text{C}}}\,\text{N}\] contain $-1$ charge, where $\text{Fe}$ has variable valency, which can show $+2$ and $+3$ oxidation number due to the presence of $s$ and $d$ electron.s
$\text{Fe}$ has electronic configuration of $3{{d}^{6}}4{{s}^{2}}$ , here $2$ electrons in $s-$ orbital while electrons in d orbital is present.
By losing $2$ electrons of $s-$ orbital it can show $+2$ oxidation state while losing $3$ electrons of $s$ &$d$ orbital combinely forms $+2$ oxidation state.
Here first we find the oxidation state of inner $\text{Fe}$.
$\text{F}{{\text{e}}_{4}}{{[\text{Fe(CN}{{\text{)}}_{6}}]}_{3}}\to 4\text{F}{{\text{e}}^{x+}}+3{{[\text{Fe(CN}{{\text{)}}_{6}}]}^{x-}}$
Here 6$\bar{CN}$ provide $6$ negative charge so total $-\text{ve}$ charge chain be $18(-\text{ve})$ which is stabilized by $\text{Fe}$ , out of $18\,(-\text{ve})$ only $6(-\text{ve})$ charge is balanced by inner $\text{Fe}$ so here
$3{{[\text{Fe(CN}{{\text{)}}_{6}}]}^{x-}}\Rightarrow 3x +(-18)=-12$
$x=+2$
Outer $\text{Fe}$ has oxidation number of $y+$ which is equal to $+12$
$4y=12$
$y=+3$
Oxidation state of $\text{Fe}=+2$ in inner complex while oxidation state of $\text{Fe}=+3$ of outer iron
Oxidation state of $\text{Fe}$ is $+2$ and $+3$ .
Note: In the modern periodic table, metals are present either in extreme left of the periodic table or in the middle of the periodic table. The elements which are present in the middle of the periodic table are called D-block elements because the last electrons are entering into the d block of the element. On the basis of partially filled d blocks they are also known as Transition elements. Transition elements are those elements which have partially filled the sub shell either in their ground state or in any of their combined state. On the basis of it, transition elements form various compounds in which variable valency of it is shown.
In a compound various elements are present which can have either positive or negative charge. In any compound, negative charge is present mainly on electronegative atoms while positive charge is present mainly on electropositive atom.
Complete step by step answer:
Given molecule is $\text{F}{{\text{e}}_{4}}{{[\text{Fe(Cn}{{\text{)}}_{6}}]}_{3}}$
Here \[\overset{-}{\mathop{\text{C}}}\,\text{N}\] contain $-1$ charge, where $\text{Fe}$ has variable valency, which can show $+2$ and $+3$ oxidation number due to the presence of $s$ and $d$ electron.s
$\text{Fe}$ has electronic configuration of $3{{d}^{6}}4{{s}^{2}}$ , here $2$ electrons in $s-$ orbital while electrons in d orbital is present.
By losing $2$ electrons of $s-$ orbital it can show $+2$ oxidation state while losing $3$ electrons of $s$ &$d$ orbital combinely forms $+2$ oxidation state.
Here first we find the oxidation state of inner $\text{Fe}$.
$\text{F}{{\text{e}}_{4}}{{[\text{Fe(CN}{{\text{)}}_{6}}]}_{3}}\to 4\text{F}{{\text{e}}^{x+}}+3{{[\text{Fe(CN}{{\text{)}}_{6}}]}^{x-}}$
Here 6$\bar{CN}$ provide $6$ negative charge so total $-\text{ve}$ charge chain be $18(-\text{ve})$ which is stabilized by $\text{Fe}$ , out of $18\,(-\text{ve})$ only $6(-\text{ve})$ charge is balanced by inner $\text{Fe}$ so here
$3{{[\text{Fe(CN}{{\text{)}}_{6}}]}^{x-}}\Rightarrow 3x +(-18)=-12$
$x=+2$
Outer $\text{Fe}$ has oxidation number of $y+$ which is equal to $+12$
$4y=12$
$y=+3$
Oxidation state of $\text{Fe}=+2$ in inner complex while oxidation state of $\text{Fe}=+3$ of outer iron
Oxidation state of $\text{Fe}$ is $+2$ and $+3$ .
Note: In the modern periodic table, metals are present either in extreme left of the periodic table or in the middle of the periodic table. The elements which are present in the middle of the periodic table are called D-block elements because the last electrons are entering into the d block of the element. On the basis of partially filled d blocks they are also known as Transition elements. Transition elements are those elements which have partially filled the sub shell either in their ground state or in any of their combined state. On the basis of it, transition elements form various compounds in which variable valency of it is shown.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

