
Calculate how much oxygen (in grams) required to combust 10 moles of magnesium from the given equation: $2Mg + {O_2} \to 2MgO$
Answer
572.1k+ views
Hint:Look at the stoichiometry of the reaction. Here, 2 moles of Mg requires 1 mole of ${O_2}$. Hence, 1 mole of Mg requires 0.5 moles of ${O_2}$. Now, calculate the number of moles of ${O_2}$ required for the combustion of 10 moles of Mg. 1 mole of ${O_2}$ weighs 32g. The molar mass of Mg is 24g/mol.
Complete step by step answer:
In the given reaction, magnesium undergoes oxidation by oxygen to form Magnesium dioxide. It is a combustion reaction.
$2Mg + {O_2} \to 2MgO$
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Before understanding how to calculate the amount of ${O_2}$ required for the reaction, let us analyze the information available from the balanced chemical equation.
Here, the reactants are magnesium and oxygen. The product formed is magnesium oxide.
The coefficients 2 for Mg and MgO are the stoichiometric coefficients. They represent the number of moles (or molecules) taking part in the reaction or formed in the reaction.
According to the given chemical reaction,
One mole of ${O_2}$ reacts with 2 moles of Mg to give 2 moles of MgO.
Therefore, 1 mole of Mg requires 0.5 moles of ${O_2}$.
Now, we need to calculate the number of moles of ${O_2}$ required to react with 10 moles of Mg.
The number of moles of ${O_2}$ required to react with 10 moles of Mg = 10 $ \times $ 0.5 = 5 moles.
We are asked to find the amount of oxygen in grams.
We know that 1 mole of oxygen gas weighs 32 g. Therefore, 5 moles weigh 5 $ \times $ 32 = 160g.
The answer is: 160g of ${O_2}$ is required for the combustion of 10 moles of Mg.
Note: Ensure that the given reaction is balanced. According to the law of conservation of mass, a balanced chemical equation has the same number of atoms of each element on both sides of the equation.
-1 mole of ${O_2}$ is equal to 22.4L. This applies to all gases.
-Remember to use the molecular mass (in grams) of oxygen and not the atomic weight. The atomic weight of oxygen is 16g/mol while the molecular mass of oxygen is 32g/mol.
Complete step by step answer:
In the given reaction, magnesium undergoes oxidation by oxygen to form Magnesium dioxide. It is a combustion reaction.
$2Mg + {O_2} \to 2MgO$
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Before understanding how to calculate the amount of ${O_2}$ required for the reaction, let us analyze the information available from the balanced chemical equation.
Here, the reactants are magnesium and oxygen. The product formed is magnesium oxide.
The coefficients 2 for Mg and MgO are the stoichiometric coefficients. They represent the number of moles (or molecules) taking part in the reaction or formed in the reaction.
According to the given chemical reaction,
One mole of ${O_2}$ reacts with 2 moles of Mg to give 2 moles of MgO.
Therefore, 1 mole of Mg requires 0.5 moles of ${O_2}$.
Now, we need to calculate the number of moles of ${O_2}$ required to react with 10 moles of Mg.
The number of moles of ${O_2}$ required to react with 10 moles of Mg = 10 $ \times $ 0.5 = 5 moles.
We are asked to find the amount of oxygen in grams.
We know that 1 mole of oxygen gas weighs 32 g. Therefore, 5 moles weigh 5 $ \times $ 32 = 160g.
The answer is: 160g of ${O_2}$ is required for the combustion of 10 moles of Mg.
Note: Ensure that the given reaction is balanced. According to the law of conservation of mass, a balanced chemical equation has the same number of atoms of each element on both sides of the equation.
-1 mole of ${O_2}$ is equal to 22.4L. This applies to all gases.
-Remember to use the molecular mass (in grams) of oxygen and not the atomic weight. The atomic weight of oxygen is 16g/mol while the molecular mass of oxygen is 32g/mol.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

