
By which of the following reactions is borazine prepared?
(A) ${B_2}{H_6} + N{H_3}\left( {excess} \right) \overset{low temperature}{\rightarrow} $
(B) ${B_2}{H_6} + N{H_3}\left( {excess} \right) \overset{high temperature}{\rightarrow} $
(C) ${{B_2}{H_6} + N{H_3}\left( {excess} \right) \overset{high temperature; ratio; 2NH3:1B2H6}{\rightarrow} }$
(D) None of these
Answer
564.6k+ views
Hint:We know that borazine has the same structure like benzene so it is also known as inorganic benzene. This inorganic benzene known as borazine has a molecular formula of ${B_3}{N_3}{H_6}$.
Complete answer:We all know that the diboranes is the simplest and a very important inorganic compound. It is an important reagent in the synthesis of many organic compounds. It is normally prepared in situ. It is a very versatile reagent for the preparation of organoboranes, which is an important intermediate in organic synthesis. Diborane is also a powerful electrophilic reagent used for the preparation of certain functional groups. Diborane was first prepared by Alfred stock by heating magnesium and boron to give magnesium boride and then treated with orthophosphoric acid.
All the boron’s act as a Lewis acid as they can easily accept electron pairs (as the central element boron has electrons less than eight i.e. it contains only six electrons). Due to which they can easily react with ammonia as nitrogen contains lone pairs which can share with boron elements to complete its octet electronic configuration.
The boranes will form different compounds with the ammonia, the final product is depending on the conditions used for the reaction.
The borazine is formed when ammonia and diborane will react in a simple ratio of \[2:1\] at a high temperature.
${{B_2}{H_6} + N{H_3}\left( {excess} \right) \overset{high temperature; ratio; 2NH3:1B2H6}{\rightarrow}} {B_3}{N_3}{H_6}$
Ammonia contains a lone pair of electrons which gets attracted towards the vacant p orbitals of boron and leads to the formation of the final product borazine.
Thus, the correct option is (C) .
Note:Diborane is also a colorless gas and it must be handled with care as it is highly reactive. It catches fire spontaneously and explodes with dioxygen. The heat of combustion is very high. In the laboratory it is handled in a vacuum frame.
Complete answer:We all know that the diboranes is the simplest and a very important inorganic compound. It is an important reagent in the synthesis of many organic compounds. It is normally prepared in situ. It is a very versatile reagent for the preparation of organoboranes, which is an important intermediate in organic synthesis. Diborane is also a powerful electrophilic reagent used for the preparation of certain functional groups. Diborane was first prepared by Alfred stock by heating magnesium and boron to give magnesium boride and then treated with orthophosphoric acid.
All the boron’s act as a Lewis acid as they can easily accept electron pairs (as the central element boron has electrons less than eight i.e. it contains only six electrons). Due to which they can easily react with ammonia as nitrogen contains lone pairs which can share with boron elements to complete its octet electronic configuration.
The boranes will form different compounds with the ammonia, the final product is depending on the conditions used for the reaction.
The borazine is formed when ammonia and diborane will react in a simple ratio of \[2:1\] at a high temperature.
${{B_2}{H_6} + N{H_3}\left( {excess} \right) \overset{high temperature; ratio; 2NH3:1B2H6}{\rightarrow}} {B_3}{N_3}{H_6}$
Ammonia contains a lone pair of electrons which gets attracted towards the vacant p orbitals of boron and leads to the formation of the final product borazine.
Thus, the correct option is (C) .
Note:Diborane is also a colorless gas and it must be handled with care as it is highly reactive. It catches fire spontaneously and explodes with dioxygen. The heat of combustion is very high. In the laboratory it is handled in a vacuum frame.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

