Answer

Verified

407.1k+ views

Hint- Here, we will be obtaining the values of the missing numbers by cross multiplication.

Here let us suppose the missing number be \[x = {\text{ }}\square \]. Now, we will cross multiply the equation and find the value of \[x\].

\[{\text{(a)}}\] Let \[\dfrac{2}{7} = \dfrac{8}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 2x = 8 \times 7 \Rightarrow 2x = 56 \Rightarrow x = 28\].

Therefore, the correct equation is \[\dfrac{2}{7} = \dfrac{8}{{28}}\].

\[{\text{(b)}}\] Let \[\dfrac{5}{8} = \dfrac{{10}}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 5x = 8 \times 10 \Rightarrow 5x = 80 \Rightarrow x = 16\].

Therefore, the correct equation is \[\dfrac{5}{8} = \dfrac{{10}}{{16}}\].

\[{\text{(c)}}\] Let \[\dfrac{{45}}{{60}} = \dfrac{{15}}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 45x = 60 \times 15 \Rightarrow x = \dfrac{{60 \times 15}}{{45}} \Rightarrow x = 20\]

Therefore, the correct equation is \[\dfrac{{45}}{{60}} = \dfrac{{15}}{{20}}\].

\[{\text{(d)}}\] Let \[\dfrac{{18}}{{24}} = \dfrac{x}{4}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 4 \times 18 = 24x \Rightarrow x = \dfrac{{4 \times 18}}{{24}} \Rightarrow x = 3\]

Therefore, the correct equation is\[\dfrac{{18}}{{24}} = \dfrac{3}{4}\].

Note- These types of problems are solved by simply cross multiplying the given equation with one unknown and then finally solving for that unknown.

Here let us suppose the missing number be \[x = {\text{ }}\square \]. Now, we will cross multiply the equation and find the value of \[x\].

\[{\text{(a)}}\] Let \[\dfrac{2}{7} = \dfrac{8}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 2x = 8 \times 7 \Rightarrow 2x = 56 \Rightarrow x = 28\].

Therefore, the correct equation is \[\dfrac{2}{7} = \dfrac{8}{{28}}\].

\[{\text{(b)}}\] Let \[\dfrac{5}{8} = \dfrac{{10}}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 5x = 8 \times 10 \Rightarrow 5x = 80 \Rightarrow x = 16\].

Therefore, the correct equation is \[\dfrac{5}{8} = \dfrac{{10}}{{16}}\].

\[{\text{(c)}}\] Let \[\dfrac{{45}}{{60}} = \dfrac{{15}}{x}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 45x = 60 \times 15 \Rightarrow x = \dfrac{{60 \times 15}}{{45}} \Rightarrow x = 20\]

Therefore, the correct equation is \[\dfrac{{45}}{{60}} = \dfrac{{15}}{{20}}\].

\[{\text{(d)}}\] Let \[\dfrac{{18}}{{24}} = \dfrac{x}{4}\]

Now cross multiplying the above equation, we get

\[ \Rightarrow 4 \times 18 = 24x \Rightarrow x = \dfrac{{4 \times 18}}{{24}} \Rightarrow x = 3\]

Therefore, the correct equation is\[\dfrac{{18}}{{24}} = \dfrac{3}{4}\].

Note- These types of problems are solved by simply cross multiplying the given equation with one unknown and then finally solving for that unknown.

Recently Updated Pages

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Define absolute refractive index of a medium

Find out what do the algal bloom and redtides sign class 10 biology CBSE

Prove that the function fleft x right xn is continuous class 12 maths CBSE

Find the values of other five trigonometric functions class 10 maths CBSE

Find the values of other five trigonometric ratios class 10 maths CBSE

Trending doubts

How do you solve x2 11x + 28 0 using the quadratic class 10 maths CBSE

Which neighbouring country does not share a boundary class 9 social science CBSE

The highest peak in Annamalai hills is aAnaimudi bDodabetta class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Which places in India experience sunrise first and class 9 social science CBSE

The highest peak of South India is A Doda Betta B Guru class 8 social science CBSE

Banaras Hindu University was founded by A CR Das B class 12 social science CBSE

Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE

Which is the largest saltwater lake in India A Chilika class 8 social science CBSE