Question

: By how much does 1 exceeds $2x-3y-4$ ?

Answer 1

Hint: We simply have to find the difference of 1 and $2x-3y-4$ which will land us to the solution.
Formula:
 $Z=1-A$
Where, A is the given equation for which we need to find the exceeded value, in this case its $2x-3y-4$
Z is the value by which 1 exceeds the expression A, in this case its $2x-3y-4$

Complete step-by-step answer:
Given the value $2x-3y-4$
We have to find the value for which the number 1 exceeds from the given value i.e. $2x-3y-4$
Not let us consider the given expression as A
i.e. $A=2x-3y-4$
Now let us consider the value by which 1 exceeds the expression A as Z i.e. 1 exceeds $A=2x-3y-4$ by:
 $Z=1-A$
 $\Rightarrow Z=1-(2x-3y-4)$
Opening the bracket we get $1-2x+3y+4$
i.e. $Z=1+4+3y-2x$
Hence, $Z=3y-2x+5$
Therefore 1 will exceed $2x-3y-4$ by $3y-2x+5$
So, the correct answer is “ $3y-2x+5$ ”.

Note: You may confuse in between $Z=1-A$ and $Z=A-1$ but do kindly remember we have to find the value by which 1 exceeds the given expression $2x-3y-4$ , which means the expression’s value is less than 1 so it will be subtracted from 1.