Question

: By how much does 1 exceeds $ 2x - 3y - 4 $ ?

Answer 1

Hint: We simply have to find the difference of 1 and $ 2x - 3y - 4 $ which will land us to the solution.
Formula:
 $ Z = 1 - A $
Where, A is the given equation for which we need to find the exceeded value, in this case its $ 2x - 3y - 4 $
Z is the value by which 1 exceeds the expression A, in this case its $ 2x - 3y - 4 $

Complete step-by-step answer:
Given the value $ 2x - 3y - 4 $
We have to find the value for which the number 1 exceeds from the given value i.e. $ 2x - 3y - 4 $
Not let us consider the given expression as A
i.e. $ A = 2x - 3y - 4 $
Now let us consider the value by which 1 exceeds the expression A as Z i.e. 1 exceeds $ A = 2x - 3y - 4 $ by:
 $ Z = 1 - A $
 $ \Rightarrow Z = 1 - (2x - 3y - 4) $
Opening the bracket we get $ 1 - 2x + 3y + 4 $
i.e. $ Z = 1 + 4 + 3y - 2x $
Hence, $ Z = 3y - 2x + 5 $
Therefore 1 will exceed $ 2x - 3y - 4 $ by $ 3y - 2x + 5 $
So, the correct answer is “ $ 3y - 2x + 5 $ ”.

Note: You may confuse in between $ Z = 1 - A $ and $ Z = A - 1 $ but do kindly remember we have to find the value by which 1 exceeds the given expression $ 2x - 3y - 4 $ , which means the expression’s value is less than 1 so it will be subtracted from 1.