Answer

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**Hint**: We simply have to find the difference of 1 and $ 2x - 3y - 4 $ which will land us to the solution.

Formula:

$ Z = 1 - A $

Where, A is the given equation for which we need to find the exceeded value, in this case its $ 2x - 3y - 4 $

Z is the value by which 1 exceeds the expression A, in this case its $ 2x - 3y - 4 $

**Complete step-by-step answer**:

Given the value $ 2x - 3y - 4 $

We have to find the value for which the number 1 exceeds from the given value i.e. $ 2x - 3y - 4 $

Not let us consider the given expression as A

i.e. $ A = 2x - 3y - 4 $

Now let us consider the value by which 1 exceeds the expression A as Z i.e. 1 exceeds $ A = 2x - 3y - 4 $ by:

$ Z = 1 - A $

$ \Rightarrow Z = 1 - (2x - 3y - 4) $

Opening the bracket we get $ 1 - 2x + 3y + 4 $

i.e. $ Z = 1 + 4 + 3y - 2x $

Hence, $ Z = 3y - 2x + 5 $

Therefore 1 will exceed $ 2x - 3y - 4 $ by $ 3y - 2x + 5 $

**So, the correct answer is “ $ 3y - 2x + 5 $ ”.**

**Note**: You may confuse in between $ Z = 1 - A $ and $ Z = A - 1 $ but do kindly remember we have to find the value by which 1 exceeds the given expression $ 2x - 3y - 4 $ , which means the expression’s value is less than 1 so it will be subtracted from 1.

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