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# : By how much does 1 exceeds $2x - 3y - 4$ ?

Last updated date: 13th Jun 2024
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Hint: We simply have to find the difference of 1 and $2x - 3y - 4$ which will land us to the solution.
Formula:
$Z = 1 - A$
Where, A is the given equation for which we need to find the exceeded value, in this case its $2x - 3y - 4$
Z is the value by which 1 exceeds the expression A, in this case its $2x - 3y - 4$

Given the value $2x - 3y - 4$
We have to find the value for which the number 1 exceeds from the given value i.e. $2x - 3y - 4$
Not let us consider the given expression as A
i.e. $A = 2x - 3y - 4$
Now let us consider the value by which 1 exceeds the expression A as Z i.e. 1 exceeds $A = 2x - 3y - 4$ by:
$Z = 1 - A$
$\Rightarrow Z = 1 - (2x - 3y - 4)$
Opening the bracket we get $1 - 2x + 3y + 4$
i.e. $Z = 1 + 4 + 3y - 2x$
Hence, $Z = 3y - 2x + 5$
Therefore 1 will exceed $2x - 3y - 4$ by $3y - 2x + 5$
So, the correct answer is “ $3y - 2x + 5$ ”.

Note: You may confuse in between $Z = 1 - A$ and $Z = A - 1$ but do kindly remember we have to find the value by which 1 exceeds the given expression $2x - 3y - 4$ , which means the expression’s value is less than 1 so it will be subtracted from 1.