What is the Binomial expansion of ${{\left( 2x+3 \right)}^{4}}$?
Answer
555.6k+ views
Hint: To obtain the binomial expansion of the expression given use Binomial Theorem. Firstly we will use the binomial theorem to expand the power of the expression. Then by using factorial and combination formulas we will simplify the equation further. Finally we will solve the equation and get the desired answer.
Complete step by step solution:
We have to find Binomial Expansion of the binomial expression:
${{\left( 2x+3 \right)}^{4}}$……$\left( 1 \right)$
The Binomial Theorem state that if we have to solve the below expression the formula used is:
${{\left( x+y \right)}^{n}}=\sum\nolimits_{r=0}^{n}{{{x}^{n-r}}{{y}^{r}}{}^{n}{{C}_{r}}}$……$\left( 2 \right)$
Where,
$x,y=$ Any real numbers/variables
$n=$ Any positive integer
$r=$ Natural number that takes value from 0 to $n$
On comparing equation (1) and (2) we get the values as:
$n=4$
$x=2x$
$y=3$
So equation (1) can be written as below:
${{\left( 2x+3 \right)}^{4}}=\sum\nolimits_{r=0}^{4}{{{\left( 2x \right)}^{4-r}}{{\left( 3 \right)}^{r}}{}^{4}{{C}_{r}}}$
On expanding the above equation and simplifying it we get,
$\begin{align}
& \Rightarrow \left( {{\left( 2x \right)}^{4-0}}{{\left( 3 \right)}^{0}}{}^{4}{{C}_{0}} \right)+\left( {{\left( 2x \right)}^{4-1}}{{\left( 3 \right)}^{1}}{}^{4}{{C}_{1}} \right)+\left( {{\left( 2x \right)}^{4-2}}{{\left( 3 \right)}^{2}}{}^{4}{{C}_{2}} \right)+\left( {{\left( 2x \right)}^{4-3}}{{\left( 3 \right)}^{3}}{}^{4}{{C}_{3}} \right)+\left( {{\left( 2x \right)}^{4-4}}{{\left( 3 \right)}^{4}}{}^{4}{{C}_{4}} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times {}^{4}{{C}_{0}} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times {}^{4}{{C}_{1}} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times {}^{4}{{C}_{2}} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times {}^{4}{{C}_{3}} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times {}^{4}{{C}_{4}} \right) \\
\end{align}$
Now we will use combination formula in above value which is given as below:
${}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}$
Where $n!=n\times \left( n-1 \right)\times \left( n-2 \right)\times .........\times 1$
Using above formula in our equation and simplifying we get,
$\begin{align}
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times \dfrac{4!}{0!\left( 4-0 \right)!} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times \dfrac{4!}{1!\left( 3-1 \right)!} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times \dfrac{4!}{2!\left( 4-2 \right)!} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times \dfrac{4!}{3!\left( 4-3 \right)!} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times \dfrac{4!}{4!\left( 4-4 \right)!} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times \dfrac{4!}{1\times 4!} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times \dfrac{4!}{1!\times 3!} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times \dfrac{4!}{2!\times 2!} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times \dfrac{4!}{3!\times 1!} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times \dfrac{4!}{4!\times 0!} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times 1 \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times 4 \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times 6 \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times 4 \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times 1 \right) \\
& \Rightarrow 16{{x}^{4}}+96{{x}^{3}}+216{{x}^{2}}+216x+81 \\
\end{align}$
Hence binomial expansion of ${{\left( 2x+3 \right)}^{4}}$ is $16{{x}^{4}}+96{{x}^{3}}+216{{x}^{2}}+216x+81$.
Note: To solve problems of binomial expansion Binomial theorem is widely used although the calculation part does get complicated but it is still preferred. A binomial expression is an algebraic expression which has two terms connected by plus or minus sign. The coefficient of each term is known as binomial coefficient. The two formulas that one needs to know for using Binomial theorem is Combination and factorial. The coefficient of the binomial terms can be found by another method known as Pascal’s method.
Complete step by step solution:
We have to find Binomial Expansion of the binomial expression:
${{\left( 2x+3 \right)}^{4}}$……$\left( 1 \right)$
The Binomial Theorem state that if we have to solve the below expression the formula used is:
${{\left( x+y \right)}^{n}}=\sum\nolimits_{r=0}^{n}{{{x}^{n-r}}{{y}^{r}}{}^{n}{{C}_{r}}}$……$\left( 2 \right)$
Where,
$x,y=$ Any real numbers/variables
$n=$ Any positive integer
$r=$ Natural number that takes value from 0 to $n$
On comparing equation (1) and (2) we get the values as:
$n=4$
$x=2x$
$y=3$
So equation (1) can be written as below:
${{\left( 2x+3 \right)}^{4}}=\sum\nolimits_{r=0}^{4}{{{\left( 2x \right)}^{4-r}}{{\left( 3 \right)}^{r}}{}^{4}{{C}_{r}}}$
On expanding the above equation and simplifying it we get,
$\begin{align}
& \Rightarrow \left( {{\left( 2x \right)}^{4-0}}{{\left( 3 \right)}^{0}}{}^{4}{{C}_{0}} \right)+\left( {{\left( 2x \right)}^{4-1}}{{\left( 3 \right)}^{1}}{}^{4}{{C}_{1}} \right)+\left( {{\left( 2x \right)}^{4-2}}{{\left( 3 \right)}^{2}}{}^{4}{{C}_{2}} \right)+\left( {{\left( 2x \right)}^{4-3}}{{\left( 3 \right)}^{3}}{}^{4}{{C}_{3}} \right)+\left( {{\left( 2x \right)}^{4-4}}{{\left( 3 \right)}^{4}}{}^{4}{{C}_{4}} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times {}^{4}{{C}_{0}} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times {}^{4}{{C}_{1}} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times {}^{4}{{C}_{2}} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times {}^{4}{{C}_{3}} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times {}^{4}{{C}_{4}} \right) \\
\end{align}$
Now we will use combination formula in above value which is given as below:
${}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!}$
Where $n!=n\times \left( n-1 \right)\times \left( n-2 \right)\times .........\times 1$
Using above formula in our equation and simplifying we get,
$\begin{align}
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times \dfrac{4!}{0!\left( 4-0 \right)!} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times \dfrac{4!}{1!\left( 3-1 \right)!} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times \dfrac{4!}{2!\left( 4-2 \right)!} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times \dfrac{4!}{3!\left( 4-3 \right)!} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times \dfrac{4!}{4!\left( 4-4 \right)!} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times \dfrac{4!}{1\times 4!} \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times \dfrac{4!}{1!\times 3!} \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times \dfrac{4!}{2!\times 2!} \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times \dfrac{4!}{3!\times 1!} \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times \dfrac{4!}{4!\times 0!} \right) \\
& \Rightarrow \left( {{\left( 2x \right)}^{4}}\times 1\times 1 \right)+\left( {{\left( 2x \right)}^{3}}\times 3\times 4 \right)+\left( {{\left( 2x \right)}^{2}}\times {{\left( 3 \right)}^{2}}\times 6 \right)+\left( {{\left( 2x \right)}^{1}}\times {{\left( 3 \right)}^{3}}\times 4 \right)+\left( 1\times {{\left( 3 \right)}^{4}}\times 1 \right) \\
& \Rightarrow 16{{x}^{4}}+96{{x}^{3}}+216{{x}^{2}}+216x+81 \\
\end{align}$
Hence binomial expansion of ${{\left( 2x+3 \right)}^{4}}$ is $16{{x}^{4}}+96{{x}^{3}}+216{{x}^{2}}+216x+81$.
Note: To solve problems of binomial expansion Binomial theorem is widely used although the calculation part does get complicated but it is still preferred. A binomial expression is an algebraic expression which has two terms connected by plus or minus sign. The coefficient of each term is known as binomial coefficient. The two formulas that one needs to know for using Binomial theorem is Combination and factorial. The coefficient of the binomial terms can be found by another method known as Pascal’s method.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

How many of the following diseases can be studied with class 11 biology CBSE

Which of the following enzymes is used for carboxylation class 11 biology CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

