Question

What is the balanced equation for the chemical reaction
$M{{g}_{3}}{{N}_{2}}+2{{H}_{2}}O\to Mg{{\left( OH \right)}_{2}}+N{{H}_{3}}$ ?

Answer 1

Hint: Balancing the equation is the prime most task when we need to understand the chemical reaction taking place in the proper proportions. It is also when we have to solve the illustration based on the same.

Complete answer:
Let us understand the basics of the balancing of any chemical reaction;
Balancing the equation means to balance the stoichiometric coefficients which would denote equal moles of any component on both the sides of the reaction. There are specific steps to balance any chemical equation depending upon the type of the chemical reaction taking place in the medium.
Thus, for given simpler reactions normal steps such as hit and trial method, are to be used.
Given;
$M{{g}_{3}}{{N}_{2}}+2{{H}_{2}}O\to Mg{{\left( OH \right)}_{2}}+N{{H}_{3}}$; to balance this reaction, try to balance the stoichiometry of the reaction.
Using some hit and trials, we get the balanced equation as;
$M{{g}_{3}}{{N}_{2\left( s \right)}}+6{{H}_{2}}{{O}_{\left( l \right)}}\to 3Mg{{\left( OH \right)}_{2\left( aq \right)}}+2N{{H}_{3\left( aq \right)}}$

Note:
Do note that balancing the equation means balancing the stoichiometric coefficients and not the subscripts. Do not try to manipulate the subscripts of any compound taking part in the reaction as reactant or the product formed.