
What is the balanced chemical equation for the synthesis of sodium bromide from sodium and bromine?
Answer
520.8k+ views
Hint: The balanced chemical equation justifies the reaction taking place with equal moles on either side of the reaction. It is the necessary step while describing any reaction and solving any illustration related to that further.
Sodium exists as a Na i.e. monatomic form whereas bromine exists as $B{{r}_{2}}$ i.e. diatomic form.
Complete answer:
Let us solve the given query;
We know that we need to synthesize sodium bromide i.e. $NaBr$ from sodium and bromine. Here, the equation stoichiometry will depend upon the diatomic molecule i.e. bromine.
Thus, this can be simply given as;
$Na+B{{r}_{2}}\to NaBr$ but this is not the balanced equation. To balance it, we need to balance the number of moles of reactant and product.
The balanced equation is given as;
\[2Na+B{{r}_{2}}\to 2NaBr\]
Note:
Do note that the balanced equation demands for the equal number of moles on both sides not equal number of atoms. Also, while balancing any reaction, focus that we need to change the stoichiometric coefficients and not the subscripts.
The reaction $N{{a}_{\left( s \right)}}+\dfrac{1}{2}B{{r}_{2\left( l \right)}}\to NaBr$ can also be called as balanced reaction but for convenience we write the same by multiplying the same by 2 (as stated above).
Sodium exists as a Na i.e. monatomic form whereas bromine exists as $B{{r}_{2}}$ i.e. diatomic form.
Complete answer:
Let us solve the given query;
We know that we need to synthesize sodium bromide i.e. $NaBr$ from sodium and bromine. Here, the equation stoichiometry will depend upon the diatomic molecule i.e. bromine.
Thus, this can be simply given as;
$Na+B{{r}_{2}}\to NaBr$ but this is not the balanced equation. To balance it, we need to balance the number of moles of reactant and product.
The balanced equation is given as;
\[2Na+B{{r}_{2}}\to 2NaBr\]
Note:
Do note that the balanced equation demands for the equal number of moles on both sides not equal number of atoms. Also, while balancing any reaction, focus that we need to change the stoichiometric coefficients and not the subscripts.
The reaction $N{{a}_{\left( s \right)}}+\dfrac{1}{2}B{{r}_{2\left( l \right)}}\to NaBr$ can also be called as balanced reaction but for convenience we write the same by multiplying the same by 2 (as stated above).
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