
Balance the following equation?
$Ca{(OH)_2}(s)$ $ + $ ${(N{H_4})_2}S{O_4}(s)$ $ \to $ $CaS{O_4}(s)$$ + $${H_2}O(l)$$ + $$N{H_3}(g)$
Answer
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Hint: An acid-base reaction is a chemical reaction that happens when an acid reacts with a base. It can be used to the pH of a solution. Several theoretical frameworks, known as acid-base theories, present diverse ideas of reaction mechanisms and their use in solving associated problems. For example, the Bronsted–Lowry acid-base theory.
Complete answer:
$Ca{(OH)_2}$ also known as slaked lime is a source of hydroxide ions when dissolved in aqueous solutions. Therefore this compound is Base. ${(N{H_4})_2}S{O_4}$ is a salt of a weak base, $N{H_4}OH$ and a strong acid ${H_2}S{O_4}$. The Number of $O{H^ - }$ ions obtained $N{H_4}OH$ is less than the number of ${H^ + }$ ions obtained from ${H_{_2}}S{O_4}$ .
After complete neutralization of $O{H^ - }$ ions by ${H^ + }$ions, there are some $7{H^ + }$ ions. Hence the aqueous solution ${(N{H_4})_2}S{O_4}$ is acidic.
So the Equation be like
$N{H_4}$ $ + $ $O{H^ - }$ $ \to $ $N{H_3}$ $ + $ ${H_2}O$ .
$Ca{(OH)_2}$ $ + $ ${(NH)_2}S{O_4}$ $ \to $ $CaS{O_4}$ $ + $ $2{H_2}O$ $ + $ $2N{H_3}$ .
Additional Information:
The amounts of the reactants and products must be modified to balance the equation. By putting coefficients in front of the appropriate formulas as needed. Never modify the subscripts when balancing an equation because this changes the substance. The balance equations are a set of equations that characterize the equilibrium distribution of products and reactants. To balance the equation one should remember the oxidation state of metal. Depending on the compound oxidation state may be varied.
Note:
The main rule to remember while balancing equations is that we can only change the coefficients. These are the numbers in front of the atoms. The numbers after the atoms have subscripts that cannot be changed. The process of balancing a chemical equation is one of trial and error. The amounts of the reactants and products must be modified to balance the equation.
Complete answer:
$Ca{(OH)_2}$ also known as slaked lime is a source of hydroxide ions when dissolved in aqueous solutions. Therefore this compound is Base. ${(N{H_4})_2}S{O_4}$ is a salt of a weak base, $N{H_4}OH$ and a strong acid ${H_2}S{O_4}$. The Number of $O{H^ - }$ ions obtained $N{H_4}OH$ is less than the number of ${H^ + }$ ions obtained from ${H_{_2}}S{O_4}$ .
After complete neutralization of $O{H^ - }$ ions by ${H^ + }$ions, there are some $7{H^ + }$ ions. Hence the aqueous solution ${(N{H_4})_2}S{O_4}$ is acidic.
So the Equation be like
$N{H_4}$ $ + $ $O{H^ - }$ $ \to $ $N{H_3}$ $ + $ ${H_2}O$ .
$Ca{(OH)_2}$ $ + $ ${(NH)_2}S{O_4}$ $ \to $ $CaS{O_4}$ $ + $ $2{H_2}O$ $ + $ $2N{H_3}$ .
Additional Information:
The amounts of the reactants and products must be modified to balance the equation. By putting coefficients in front of the appropriate formulas as needed. Never modify the subscripts when balancing an equation because this changes the substance. The balance equations are a set of equations that characterize the equilibrium distribution of products and reactants. To balance the equation one should remember the oxidation state of metal. Depending on the compound oxidation state may be varied.
Note:
The main rule to remember while balancing equations is that we can only change the coefficients. These are the numbers in front of the atoms. The numbers after the atoms have subscripts that cannot be changed. The process of balancing a chemical equation is one of trial and error. The amounts of the reactants and products must be modified to balance the equation.
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