Question

Balance the chemical equation given below and calculate the number of moles of $N{{H}_{4}}Cl$ formed when 16 moles of $N{{H}_{3}}$ react with 6 moles of $C{{l}_{2}}$ gas.
\[N{{H}_{3}}+C{{l}_{2}}\to {{N}_{2}}+N{{H}_{4}}Cl\]

Answer 1

Hint The general concept of the chemistry which tells about how to balance a chemical equation includes the concept which says that the number of moles of each atom in the reactant side should equal to that in the product side and also number of moles is found on the basis of this balanced equation.

Complete step – by – step answer:
In the lower classes of chemistry, we have studied about the concept of balancing the given chemical equation and also about how to interpret it.
We shall now recall the concept so that we can derive the required answer.
- A chemical equation is nothing but the interpretation of the substances which reacts together to form a new or modified substance.
- The compounds which react with each other are called reactants and the compounds which are newly formed are called as the products.
- The reactants are written on the left hand side of the reaction and products on the right hand side of the equation which is separated by an arrow that represents the reaction going from hand right to left hand side.
- Balancing of this chemical equation is nothing but making the number of moles of each atom on the reactant side to be equal to that of the product side.
In the given reaction\[N{{H}_{3}}+C{{l}_{2}}\to {{N}_{2}}+N{{H}_{4}}Cl\], the balanced equation will be
\[8N{{H}_{3}}+3C{{l}_{2}}\to 6N{{H}_{4}}Cl+{{N}_{2}}\]
Here, according to the above balanced equation 8 moles of ammonia reacts with 3 moles of chlorine to give 6 moles of ammonium chloride and one mole of nitrogen.
To get 16 moles of ammonia, we have to double the amount of the reaction and therefore the reaction becomes,
\[16N{{H}_{3}}+6C{{l}_{2}}\to 12N{{H}_{4}}Cl+2{{N}_{2}}\]

Therefore, 12 moles of ammonium chloride is formed when 16 moles of ammonia reacts with 6 moles of chlorine.

Note: Note that balancing a chemical equation is to be done carefully by looking into both reactant and product side and double checking the number of moles on both sides of the reactions and then proceeding to the necessary answers.