Question

Balance following reaction-
\[N{{a}_{2}}C{{o}_{3\left( s \right)}}+HC{{I}_{\left( aq \right)}}\to NaC{{l}_{\left( aq \right)}}+{{H}_{2}}{{O}_{\left( \ell \right)}}+C{{O}_{2\left( g \right)}}\]

Answer 1

Hint: Above reaction is the example of a double displacement reaction in such a reaction one component from the both reacting molecules get exchanged to form the product.

Complete step by step answer:
Suppose the first reactant molecule is \[AB\] similarly the second recanting molecule is \[CD\] when they both react with each other then they give product \[AD\] and \[CB\] expression as follows.
\[AB+CD\to AD+CB\]
Here, get react with \[D\] and form \[AD\] and \[B\] get react with \[B\] and form \[CB\]. We have to discuss here, reaction between sodium carbonate \[N{{a}_{2}}C{{o}_{3}}\] and hydrochloric acid \[\left( HCl \right)\].
Reaction Explanation:-
First- \[N{{a}_{2}}C{{o}_{3}}+2HCI\to 2NaC{{l}_{\left( aq \right)}}+{{H}_{2}}C{{O}_{3\left( aq \right)}}\]
Second - \[{{H}_{2}}C{{O}_{3}}\to {{H}_{2}}{{O}_{\left( \ell \right)}}+C{{O}_{2\left( g \right)}}\]
In first step of reaction we have that for balancing the both side of chemical reaction we have to put one mole of sodium carbonate and for this we have to add two moles of hydrochloric acid, As product we have two moles of sodium chloride and one mole of bicarbonate or hydrogen carbonate. Hydrogen carbonate bubbles have colourless gas which is carbon dioxide.
When both reactants are mixed together then evolution of gas will take place.
When we compare the right hand side and left hand side of the above reaction and counting the number of atoms then counting should be the same in the right hand side and left hand side.
Number of sodium atoms in the right hand side and left hand side is two.
Number of carbon atoms is one on each side.
Number of oxygen atoms is there on both sides.
Number of hydrogen atoms is one on each side.
Number of chlorine atoms is one on both sides.

Note: Hence, for balancing any chemical reaction all atoms in the left hand side and in the right hand side should be the same in numbers.
Always remember that the number of atoms should always be the same on both sides of reaction.