
How many atoms of sodium (Na) are in $2.5$mole of sodium?
Answer
551.1k+ views
Hint: We will use the Avogadro number to determine the number of atoms in the given mol. By multiplying the given mole with the Avogadro number we will determine the numbers of atoms. According to the Avogadro, one mole of any substance contains$\,6.02 \times {10^{23}}$ atoms, molecules or ions of that substance.
Complete solution:
According to the Avogadro number, $\,6.02 \times {10^{23}}$ atoms are present in one mole of any substance and this number,$\,6.02 \times {10^{23}}$ is known as Avogadro number.
According to the Avogadro number,
One mole of any substance =$\,6.02 \times {10^{23}}$ atoms
So,
One mole sodium =$\,6.02 \times {10^{23}}$ atoms of sodium
So, $2.5$moles of sodium will have,
$2.5$mole of sodium =$\,6.02 \times {10^{23}} \times 2.5$ atoms of sodium
=$\,1.5 \times {10^{24}}$ atoms of sodium
So, $\,1.5 \times {10^{24}}$atoms of sodium are present in $2.5$mol of chlorine.
Therefore, $\,1.5 \times {10^{24}}$ sodium atoms is the correct answer.
Additional information: Most of the time direct moles of the substance are not given. If in place of moles gram amount is given then we have to calculate the moles of that substance first. For this, we use the mole formula. The mole formula is as follows:
${\text{mole}}\,\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,\,{\text{mass}}}}$
After calculating the moles we multiply the moles with Avogadro's number to determine the total number of atoms.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. In the case of monoatomic, one mole of a substance contains an Avogadro number of atoms. Sodium is a monatomic element. We can also determine the total number of molecules and ions by using the Avogadro number. For this, we have to multiply the Avogadro with a total number of molecules or ions.
Complete solution:
According to the Avogadro number, $\,6.02 \times {10^{23}}$ atoms are present in one mole of any substance and this number,$\,6.02 \times {10^{23}}$ is known as Avogadro number.
According to the Avogadro number,
One mole of any substance =$\,6.02 \times {10^{23}}$ atoms
So,
One mole sodium =$\,6.02 \times {10^{23}}$ atoms of sodium
So, $2.5$moles of sodium will have,
$2.5$mole of sodium =$\,6.02 \times {10^{23}} \times 2.5$ atoms of sodium
=$\,1.5 \times {10^{24}}$ atoms of sodium
So, $\,1.5 \times {10^{24}}$atoms of sodium are present in $2.5$mol of chlorine.
Therefore, $\,1.5 \times {10^{24}}$ sodium atoms is the correct answer.
Additional information: Most of the time direct moles of the substance are not given. If in place of moles gram amount is given then we have to calculate the moles of that substance first. For this, we use the mole formula. The mole formula is as follows:
${\text{mole}}\,\,{\text{ = }}\,\dfrac{{{\text{mass}}}}{{{\text{molar}}\,\,{\text{mass}}}}$
After calculating the moles we multiply the moles with Avogadro's number to determine the total number of atoms.
Note: The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. In the case of monoatomic, one mole of a substance contains an Avogadro number of atoms. Sodium is a monatomic element. We can also determine the total number of molecules and ions by using the Avogadro number. For this, we have to multiply the Avogadro with a total number of molecules or ions.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

