
How many atoms of silicon are in \[2.50\,moles\]of $Si{O_2}$ ?
Answer
556.5k+ views
Hint: We know that there are $6.022\, \times \,{10^{23}}$ amount of particles in one mole of any atom. To solve for $2.50\,moles$ We have to multiply the amount with Avogadro number. For this type of conversion, always remember that any element or compound will have Avogadro amount of particles, atoms, molecules etc.
Complete step-by-step answer:
We know that silicon comes in the carbon family, having less catenation property than carbon. Silicon is forming its oxide silicon oxide having a formula $Si{O_2}$ where one atom of silicon is attached with two atoms of oxygen. So now we know that whenever the amount of atoms or amount of moles are asked when the moles information is given.
Let us take the help of the relation of unit one mole, we know that one mole contains $6.022\, \times \,{10^{23}}$ atoms so for calculating the amount or number of atoms in given moles we have to multiply the Avogadro number with the amount. Here it’s given that we have \[2.50\,moles\] of silicon oxide, hence the number of atoms are,
$1\,mole = \,6.022\, \times \,{10^{23}}\,atoms$
Number of particles in $2.50\,moles$ = $6.022\, \times \,{10^{23}}\, \times \,2.50\,\,atoms$
Number of particles in $2.50\,moles$ = $15.055\, \times \,{10^{23}}\,atoms\,$
Number of particles in $2.50\,moles$ = $1.5055\, \times \,{10^{24}}\,atoms\,$
Thus we get to know after calculating that $2.50\,moles$ contains $1.5055\, \times \,{10^{24}}\,atoms\,$ . This is the same as we are talking about a simple mathematical calculation for the number of balls. Suppose We have a box, in that box We have three balls now for calculating the number of balls in four same types of boxes, We have to multiply three balls with four boxes to get the total number.
Note: We have to understand this concept on the basis of moles and particles, where particles can be atoms, molecules etc. Above we have taken an example where the total numbers of balls are equal to the multiplication of balls in one box with the number of boxes. We can change the amount by shifting the decimal in left and right hand direction.
Complete step-by-step answer:
We know that silicon comes in the carbon family, having less catenation property than carbon. Silicon is forming its oxide silicon oxide having a formula $Si{O_2}$ where one atom of silicon is attached with two atoms of oxygen. So now we know that whenever the amount of atoms or amount of moles are asked when the moles information is given.
Let us take the help of the relation of unit one mole, we know that one mole contains $6.022\, \times \,{10^{23}}$ atoms so for calculating the amount or number of atoms in given moles we have to multiply the Avogadro number with the amount. Here it’s given that we have \[2.50\,moles\] of silicon oxide, hence the number of atoms are,
$1\,mole = \,6.022\, \times \,{10^{23}}\,atoms$
Number of particles in $2.50\,moles$ = $6.022\, \times \,{10^{23}}\, \times \,2.50\,\,atoms$
Number of particles in $2.50\,moles$ = $15.055\, \times \,{10^{23}}\,atoms\,$
Number of particles in $2.50\,moles$ = $1.5055\, \times \,{10^{24}}\,atoms\,$
Thus we get to know after calculating that $2.50\,moles$ contains $1.5055\, \times \,{10^{24}}\,atoms\,$ . This is the same as we are talking about a simple mathematical calculation for the number of balls. Suppose We have a box, in that box We have three balls now for calculating the number of balls in four same types of boxes, We have to multiply three balls with four boxes to get the total number.
Note: We have to understand this concept on the basis of moles and particles, where particles can be atoms, molecules etc. Above we have taken an example where the total numbers of balls are equal to the multiplication of balls in one box with the number of boxes. We can change the amount by shifting the decimal in left and right hand direction.
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