How many atoms of iron are there in 3.77 moles of Iron?
Answer
621.9k+ views
Hint: 1)Avogadro's number is a significant relationship to remember: \[1{\text{ }}mole{\text{ }} = \] \[\;6.022\times{10^{23}}\] atoms, molecules, protons, and so forth
2)To change over from moles to atoms, multiply the molar sum by Avogadro's number
Complete step by step answer:
Avogadro's number is commonly dimensionless, yet when it defines the mole, it very well may be expressed as \[6.022 \times {10^{23}}\] elementary entities/mol. This form shows the role of Avogadro's number as a conversion factor between the number of entities and the number of moles. Subsequently, given the relationship \[1{\text{ }}mol{\text{ }} = {\text{ }}6.022{\text{ }}x{\text{ }}{10^{23}}\] atoms, changing over among moles and atoms of a substance becomes a simple dimensional analysis problem.
One mole of anything is \[6.022 \times {10^{23}}\] everythings, including molecules.
Multiply the moles Fe by \[6.022 \times {10^{23}}\] particles/mol.
\[3.77{\text{ }}mol{\text{ }}Fe\] x $\dfrac{{6.022 \times 10^{23}{\text{atoms Fe}}}}{{1{\text{mol Fe}}}}$ =\[2.27 \times {10^{24}}\] molecules Fe adjusted to three significant figures
Note:
1)The measure of substance of a system that contains as numerous elementary entities as there are atoms in \[12{\text{ }}g\] of \[carbon - 12\] .
2)Avogadro's number - The number of atoms present in \[12{\text{ }}g\] of \[carbon - 12\] , which is \[6.022 \times {10^{23}}\] and the number of elementary entities (atoms or molecules) comprising one mole of a given substance.
3)From the moles of a substance, one can also locate the number of atoms in a sample and the other way around. The extension among atoms and moles is Avogadro's number, \[6.022 \times {10^{23}}.\]
4)The mole can be used to relate masses of substances to the number of atoms in them. This is an easy method of deciding the amount of one substance that can react with a given measure of another substance.
2)To change over from moles to atoms, multiply the molar sum by Avogadro's number
Complete step by step answer:
Avogadro's number is commonly dimensionless, yet when it defines the mole, it very well may be expressed as \[6.022 \times {10^{23}}\] elementary entities/mol. This form shows the role of Avogadro's number as a conversion factor between the number of entities and the number of moles. Subsequently, given the relationship \[1{\text{ }}mol{\text{ }} = {\text{ }}6.022{\text{ }}x{\text{ }}{10^{23}}\] atoms, changing over among moles and atoms of a substance becomes a simple dimensional analysis problem.
One mole of anything is \[6.022 \times {10^{23}}\] everythings, including molecules.
Multiply the moles Fe by \[6.022 \times {10^{23}}\] particles/mol.
\[3.77{\text{ }}mol{\text{ }}Fe\] x $\dfrac{{6.022 \times 10^{23}{\text{atoms Fe}}}}{{1{\text{mol Fe}}}}$ =\[2.27 \times {10^{24}}\] molecules Fe adjusted to three significant figures
Note:
1)The measure of substance of a system that contains as numerous elementary entities as there are atoms in \[12{\text{ }}g\] of \[carbon - 12\] .
2)Avogadro's number - The number of atoms present in \[12{\text{ }}g\] of \[carbon - 12\] , which is \[6.022 \times {10^{23}}\] and the number of elementary entities (atoms or molecules) comprising one mole of a given substance.
3)From the moles of a substance, one can also locate the number of atoms in a sample and the other way around. The extension among atoms and moles is Avogadro's number, \[6.022 \times {10^{23}}.\]
4)The mole can be used to relate masses of substances to the number of atoms in them. This is an easy method of deciding the amount of one substance that can react with a given measure of another substance.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

