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How many atoms of each element are present in \[1\] mole of \[{H_2}S{O_4}\]?

Answer
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Hint:A mole of substance is defined as the number of particles which is equal to \[6.023 \times {10^{23}}\] numbers of particles of that substance. A mole is used as a unit to specify the amount of a substance.

Complete step by step answer:According to the mole concept a mole of a substance contains that amount of substance which is equal to the molar mass of the substance. Thus we can say that one mole of carbon contains \[12g\] of carbon which is the molar mass of carbon. Also one mole of water contains \[18g\] of water which is the molar mass of water.
The term mole was given by a German chemist Wilhelm Ostwald in \[1896\] who describes that a large number of molecules is present in a mole of a compound. The number is \[6.023 \times {10^{23}}\] and called it as Avogadro’s number or constant denotes as \[{N_A}\] after the death of Amedeo Avogadro.
Mole is used as a unit of measurement to express the amount of a substance present in a specific weight of the substance. By definition, a mole is equal to the amount of substance which is present in \[6.023 \times {10^{23}}\] number of particles. The particles considered may be atoms or molecules or ions.
The molar mass of sulphuric acid is \[98g/mol\]. This corresponds to one mole of sulfuric acid having the chemical formula \[{H_2}S{O_4}\].
Hence the atoms of each element present in \[{H_2}S{O_4}\] are
Hydrogen = $2 \times {N_A} = 2 \times 6.023 \times {10^{23}}atoms = 12.046 \times {10^{23}}atoms.$
Sulphur = ${N_A} = 6.023 \times {10^{23}}atoms$
Oxygen = $4 \times {N_A} = 4 \times 6.023 \times {10^{23}}atoms = 24.092 \times {10^{23}}atoms.$

Note:
The mole is used as the SI unit for describing the amount of a substance. The mole calculation is very useful for determining the exact amount of a substance. Using the number of moles we can determine the amount of the reactants and the amount of products produced from a chemical reaction.