
How many atoms are contained in one mole of sucrose?
Answer
511.8k+ views
Hint: The molecular formula of sucrose is $\left( {{C_{12}}{H_{22}}{O_{11}}} \right)$. We can clearly see that sucrose contains $12$ moles of carbon atoms, $22$ moles of hydrogen atoms and $11$ moles of oxygen atoms. $1$ mole sucrose is the same as $1$ mole of sucrose atoms. Similarly, it is applicable to all the elements present in the sucrose.
Complete answer:
As we know that $1$ mole of sucrose contains$ = 6.023 \times {10^{23}}$ molecules
Because, $1$ molecule of sucrose contains $45$ atoms
Therefore, $6.023 \times {10^{23}}$ molecules of sucrose contains$ = 45 \times 6.023 \times {10^{23}}$ $\dfrac{{atoms}}{{mole}}$
After solving completely we get, $ = $$271.035 \times {10^{23}}$ $\dfrac{{atoms}}{{mole}}$
After simplifying it we get, $ = 2.71 \times {10^{25}}$$\dfrac{{atoms}}{{mole}}$
So, $6.022 \times {10^{23}}$ molecules of sucrose contains$ = 2.71 \times {10^{25}}\dfrac{{atoms}}{{mole}}$
Note:
Sucrose is a disaccharide (a molecule composed of two monosaccharide which are glucose and fructose). It is also known as common sugar, Sucrose is mainly produced naturally in plants and from that we refined the table sugar. For human use or consumption, sucrose is extracted and refined from sugarcane or sugar beet. In sucrose, the two monosaccharide that is glucose and fructose are linked by an ether bond and this bond connects $C_1$ of glucose and $C_2$ of fructose and this bonding or this linkage is called glycosidic linkage. Dehydration of sucrose gives pure carbon and water. After that carbon oxidised to carbon dioxide when it reacts with air $\left( {{O_2}} \right)$. Hydrolysis of sucrose breaks the glycosidic linkage which converts it into glucose and fructose. This process of hydrolysis is very slow in nature by which the solutions of sucrose can sit for many years with negligible amount of change in its structure or composition.
Complete answer:
As we know that $1$ mole of sucrose contains$ = 6.023 \times {10^{23}}$ molecules
Because, $1$ molecule of sucrose contains $45$ atoms
Therefore, $6.023 \times {10^{23}}$ molecules of sucrose contains$ = 45 \times 6.023 \times {10^{23}}$ $\dfrac{{atoms}}{{mole}}$
After solving completely we get, $ = $$271.035 \times {10^{23}}$ $\dfrac{{atoms}}{{mole}}$
After simplifying it we get, $ = 2.71 \times {10^{25}}$$\dfrac{{atoms}}{{mole}}$
So, $6.022 \times {10^{23}}$ molecules of sucrose contains$ = 2.71 \times {10^{25}}\dfrac{{atoms}}{{mole}}$
Note:
Sucrose is a disaccharide (a molecule composed of two monosaccharide which are glucose and fructose). It is also known as common sugar, Sucrose is mainly produced naturally in plants and from that we refined the table sugar. For human use or consumption, sucrose is extracted and refined from sugarcane or sugar beet. In sucrose, the two monosaccharide that is glucose and fructose are linked by an ether bond and this bond connects $C_1$ of glucose and $C_2$ of fructose and this bonding or this linkage is called glycosidic linkage. Dehydration of sucrose gives pure carbon and water. After that carbon oxidised to carbon dioxide when it reacts with air $\left( {{O_2}} \right)$. Hydrolysis of sucrose breaks the glycosidic linkage which converts it into glucose and fructose. This process of hydrolysis is very slow in nature by which the solutions of sucrose can sit for many years with negligible amount of change in its structure or composition.
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