Question

Atomicity of ozone molecule is:
(A) $1$
(B) $2$
(C) $3$
(D) $4$

Answer 1

Hint:
In this question, we have to discuss Atomicity and calculate the atomicity of ozone ${O_3}$ molecules based on its structure and explain about the term atomicity.

Complete step by step answer:
-Atomicity of an elementary substance is defined as the number of atoms of the element present in one molecule of the substance.
For example, each molecule of nitrogen is composed of two nitrogen atoms. So the atomicity of nitrogen gas is $2$. In older contexts, atomicity is sometimes referred to as valency.
Examples:
-Inert gases like helium, neon are monoatomic
-Hydrogen, Oxygen is diatomic
-Ozone is triatomic
-Phosphorus is tetratomic
According to question,
-The chemical formula of Ozone is ${O_3}$.
-Ozone is an allotropic form of oxygen and is diamagnetic in nature. At sea level ozone is highly reactive and causes pollution. At 20 kilometers above it is formed from oxygen in the presence of sunlight to protect the earth from ultraviolet rays.
So, here we are calculating the atomicity of elements.
$Atomicity\,of\,an\,element\, = \,Molar\,Mass\, \div \,Atomic\,Mass$
The atomic mass of $1$ oxygen atom is $16$.
Here, we have $3$ oxygen atoms.
Therefore, the molecular mass will be $16\, \times \,3 = \,48$
Substitute the value of molar mass and atomic mass in the formula
$Atomicity\,of\,an\,element\, = 48\, \div \,16\, = 3$
So, the Atomicity of Ozone is $3$.

So, Option (C) is Correct.

Note: Atomic mass is the mass of an atomic particle is called the atomic mass and Molecular mass is the amount of mass associated with a molecule. It is also called molecular weight. It can be calculated by adding the mass of each atom multiplied by the number of atoms of the element present in the molecule.