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Atmospheric pressures recorded in different cities are as follows:
CitiesShimlaBangaloreDelhiMumbai
p in \[N/{m^2}\]\[1.01 \times {10^5}\]\[1.2 \times {10^5}\]\[1.02 \times {10^5}\]\[1.21 \times {10^5}\]


Consider the above data and mark the place at which the liquid will boil first.
A. Shimla
B. Bangalore
C. Delhi
D. Mumbai

Answer
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Hint: The boiling point of the liquid depends on the atmospheric pressure. Higher the atmospheric pressure, more energy is required by the liquid to boil and the liquid will exhibit higher boiling point.

Complete step by step answer:
The boiling is defined as the process by which the substance present in liquid state changes into vapour state when heated to its boiling temperature.
Boiling point is defined as the point at which the liquid starts to boil and changes to vapor state.
The change from liquid state to vapour state occurs when the vapour pressure of the liquid becomes equal to the atmospheric pressure which is exerted on the liquid. Boiling is a physical change that does not affect the composition of the water molecule.
The pressure exerted by the gas on the liquid affects the boiling point. It is called atmospheric pressure in the open system. Higher the atmospheric pressure, more energy is required to boil and higher boiling point is required.
The atmospheric pressure of Mumbai is highest \[1.21 \times {10^5}\] so the boiling point will be high. The atmospheric pressure of Shimla is least \[1.01 \times {10^5}\] so the boiling point will be less.
Thus, among the cities liquid in Shimla will boil first.

So, the correct answer is Option A.

Note: Apart from atmospheric pressure, the boiling point of the liquid depends on the temperature, vapour pressure of the liquid.