
At what time, between nine o’clock and ten o’clock, are the hands of a clock in the opposite direction?
A. \[9\] hours \[17\dfrac{8}{{11}}\] minutes
B. \[9\] hours \[21\dfrac{9}{{11}}\] minutes
C. \[9\] hours \[23\dfrac{9}{{11}}\] minutes
D. \[9\] hours \[48\dfrac{9}{{11}}\] minutes
E. \[9\] hours \[16\dfrac{4}{{11}}\] minutes
Answer
475.2k+ views
Hint: We need to find the time at which the hands of a clock ( minute hand and hour hand ) are in the opposite direction not the whole day but between nine o’clock and ten o’clock . Between nine o’clock and ten o’clock ‘hour hand’ lies between \[9\] and \[10\]. In one hour ‘minute hand ’ gains \[{330^0}\] or \[55\] minute space .
Complete step by step answer:
We need to find at what time ‘minute hand’ will be at the opposite of ‘hour hand’ .
The large hand on a clock that points to the minute is called ‘minute hand’. The small hand denotes hour, which is why they are called ‘hour hand ’. At \[9\] o’clock ‘minute hand’ is at 12 and ‘hour hand ’ is at 9 . So at \[9\] o'clock the minute hand is behind the ‘hour hand ’ by \[9 \times 5\]= \[45\] minute space .
Minute hand will be the opposite of the hour hand if it is between \[3\] and \[4\] . As \[3\] and \[4\] is opposite of \[9\] and \[10\]. As ‘minute hand ’ between \[3\] and \[4\] means \[15\] to \[20\] minutes we can assume that ‘hour hand ’ will be near to \[9\].So ‘ minute hand’ has to gain \[3 \times 5\] = \[15\] minute space as \[3\] is opposite to \[9\]. In one hour ‘minute hand’ moves \[{360^0}\]
In one hour ‘hour hand ’ moves \[\dfrac{{{{360}^0}}}{{12}}\] = \[{30^0}\]. So In one hour ‘minute hand ’ gains \[{360^0} - {30^0} = {330^0}\] which means \[55\] minutes space . Gain of \[55\] minutes space achieved in \[60\] minutes .So gain of \[15\] minutes space achieved in \[\dfrac{{60}}{{55}} \times 15\] minutes = \[\dfrac{{180}}{{11}}\] minutes = \[16\dfrac{4}{{11}}\] minutes .
So at \[9\] hours \[16\dfrac{4}{{11}}\] minutes both the two hands of the watch will be in opposite directions between nine o’clock and ten o’clock .
Therefore, option (E) is the correct answer.
Note: Careful about minute and minute space . minute space denotes the space or angle minute hand moves but minute represents time . Be attentive about calculation how much minute space ‘minute hand’ has to gain . Be extra careful about the portion where we deduce gain of \[55\] minutes space achieved in \[60\] minutes.
Complete step by step answer:
We need to find at what time ‘minute hand’ will be at the opposite of ‘hour hand’ .
The large hand on a clock that points to the minute is called ‘minute hand’. The small hand denotes hour, which is why they are called ‘hour hand ’. At \[9\] o’clock ‘minute hand’ is at 12 and ‘hour hand ’ is at 9 . So at \[9\] o'clock the minute hand is behind the ‘hour hand ’ by \[9 \times 5\]= \[45\] minute space .
Minute hand will be the opposite of the hour hand if it is between \[3\] and \[4\] . As \[3\] and \[4\] is opposite of \[9\] and \[10\]. As ‘minute hand ’ between \[3\] and \[4\] means \[15\] to \[20\] minutes we can assume that ‘hour hand ’ will be near to \[9\].So ‘ minute hand’ has to gain \[3 \times 5\] = \[15\] minute space as \[3\] is opposite to \[9\]. In one hour ‘minute hand’ moves \[{360^0}\]
In one hour ‘hour hand ’ moves \[\dfrac{{{{360}^0}}}{{12}}\] = \[{30^0}\]. So In one hour ‘minute hand ’ gains \[{360^0} - {30^0} = {330^0}\] which means \[55\] minutes space . Gain of \[55\] minutes space achieved in \[60\] minutes .So gain of \[15\] minutes space achieved in \[\dfrac{{60}}{{55}} \times 15\] minutes = \[\dfrac{{180}}{{11}}\] minutes = \[16\dfrac{4}{{11}}\] minutes .
So at \[9\] hours \[16\dfrac{4}{{11}}\] minutes both the two hands of the watch will be in opposite directions between nine o’clock and ten o’clock .
Therefore, option (E) is the correct answer.
Note: Careful about minute and minute space . minute space denotes the space or angle minute hand moves but minute represents time . Be attentive about calculation how much minute space ‘minute hand’ has to gain . Be extra careful about the portion where we deduce gain of \[55\] minutes space achieved in \[60\] minutes.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

