Question

At Shimla, the temperature was $ - {7^\circ}C$ on Tuesday. It then dipped by ${3^\circ}C$ on Wednesday. On Thursday, it rose by ${6^\circ}C$ . What was the temperature of Shimla on Wednesday and Thursday respectively?
\[
  A.{\text{ }} - {4^\circ}C, - {10^\circ}C \\
  B.{\text{ }} - {10^\circ}C, - {4^\circ}C \\
  C.{\text{ }} - {12^\circ}C, - {8^\circ}C \\
  D.{\text{ }} - {10^\circ}C, - {40^\circ}C \\
 \]

Answer 1

Hint- In order to find the temperature on respective two days use the initial temperature on Tuesday, for a rise in temperature add that given amount of temperature and for a drop in temperature subtract the given amount of temperature.

Complete step-by-step answer:
Given that: the temperature was $ - {7^\circ}C$ on Tuesday.
It then dipped by ${3^\circ}C$ on Wednesday.
Since the temperature dipped by ${3^\circ}C$ so we will subtract ${3^\circ}C$ from the given temperature.
Temperature on Wednesday = Temperature on Tuesday - ${3^\circ}C$
So, temperature on Wednesday
$
   = - {7^\circ}C - {3^\circ}C \\
   = - {10^\circ}C \\
 $
Also given that: on Thursday, it rose by ${6^\circ}C$
Since the temperature rose by ${6^\circ}C$ so we will add ${6^\circ}C$ to the given temperature on Wednesday.
Temperature on Thursday = Temperature on Wednesday + ${6^\circ}C$
So, temperature on Thursday
$
   = - {10^\circ}C + {6^\circ}C \\
   = - {4^\circ}C \\
 $
Hence, the temperature on Wednesday was $ - {10^\circ}C$ and the temperature on Thursday was $ - {4^\circ}C$ .
So, option B is the correct option.

Note- Temperature is a physical property of matter that quantitatively expresses hot and cold. Temperature is measured by the help of a thermometer. Different units of temperature are Celsius, Fahrenheit, and Kelvin etc. In order to solve such problems, students must take care of the units mentioned and asked.