Question

At a toy store, small pandas toys cost $\$ $3.50 and giant pandas toys cost $\$ $14. If the store sold 29 pandas toys and made $\$ $217 in revenue in one week, then how many small pandas toys and giant pandas toys were sold in total?
$\left( a \right)$ 18 small panda toys, 11 giant panda toys
$\left( b \right)$ 11 small panda toys, 18 giant panda toys
$\left( c \right)$ 12 small panda toys, 17 giant panda toys
$\left( d \right)$ 18 small panda toys, 13 giant panda toys

Answer 1

Hint: In this particular question assume any variable be the number of small pandas so the number of giant pandas is (29 – x) as the total number of pandas sold is 29, so use these concepts to reach the solution of the question.

Complete step by step answer:
Given data:
At a toy store, small pandas toys cost $\$ $3.50 and giant pandas toys cost $\$ $14.
And the total pandas sold in one week = 29.
Let X number of small pandas sold in one week.
So (29 – X) number of giant pandas sold in one week as the total number of pandas sold in one week is equal to 29.
Now the sum of the multiplication of respective pandas with their respective cost is equal to the total revenue generated.
As the total revenue generated is $\$ $217.
Therefore, $3.50X + \left( {29 - X} \right)14 = 217$
Now simplify this we have,
$ \Rightarrow 3.50X + 406 - 14X = 217$
$ \Rightarrow 10.5X = 406 - 217 = 189$
$ \Rightarrow X = \dfrac{{189}}{{10.5}} = 18$.
So 18 small pandas sold in one week.
So the number of big pandas sold in one week = (29 – 18) = 11 big pandas.
So this is the required answer.

So, the correct answer is “Option A”.

Note: Whenever we face such types of questions the key concept we have to remember is that the sum of the multiplication of respective pandas with their respective cost is equal to the total revenue generated, so construct the linear equation as above and simplify we will get the required small pandas then subtract this value from 29 as above we will get the required number of giant pandas.