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Assertion: 133125is a terminating decimal fraction.
Reason: If q=2n.5m, where n, m are non-negative integers, thenpqis a terminating decimal fraction.
A. Both Assertion and Reason are correct, and Reason is the correct explanation for Assertion.
B. Both Assertion and Reason are correct, but Reason is not the correct explanation for Assertion.
C. Assertion is correct, but Reason is incorrect
D. Assertion is incorrect, but Reason is correct

Answer
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Hint:
Terminating decimal numbers are the numbers that contain a finite number of digits after the decimal point. A number 2.56 can be a terminating decimal if it is represented as 2.5600000000….. where 0 is terminating.
In this question, expand the rational numbers in terminating form, then check for terminating numbers form2n×5m, and if the condition satisfies, then find the terminating number.

Complete step by step solution:
Factorize the denominator of the given rational number in the form 2n×5mto check the terminating numbers,
 133125
By factoring the denominator, we can write 3125=5×5×5×5×5=55
Multiply the factor by 20 which is equal to20=1 bring the factors in terminating form20×55; hence we can say the rational number is in terminating form.
As we know, if the denominator is in the form of 2n×5m, then the fraction is always terminating; hence we can say the number is correct, and both Assertion and Reason are correct, and Reason is the correct explanation for Assertion.

Option A is correct.

Note:
Any rational number can be written as either a terminating or repeating decimal by dividing the numerator by denominator, and if the remainder is 0, then the number is a terminating decimal. Every fraction number can be either terminating or non-termination (or repeating).