Question

Assertion: Cs and $F_2$ combines violently to form CsF.
Reason: Cs is most electropositive and F is most electronegative.
A.Both Assertion and Reason are correct and Reason is the correct explanation for Assertion.
B.Both Assertion and Reason are correct and Reason is not the correct explanation for Assertion.
C.Assertion is correct but Reason is incorrect.
D.Both Assertion and Reason are incorrect.

Answer 1

Hint: We will write about the nature of Cs and F and then we will show the chemical reaction between these two elements. We will then carefully inspect the periodic desk and then we will find out the appropriate option from the above given options.

Complete step by step answer:
This query can be answered via carefully inspecting the periodic desk. The first critical factor to notice here is that this response will produce an ionic compound. This is the case due to the fact the detail placed in group 1 is said to donate an electron to a detail placed in organization 17, i.e. To a halogen. We can say that- Cesium, belonging to group one, donates an electron forming 1+ cations and fluorine, belonging to group 17, accepts an electron forming 1- anions. The Chemical components for this ionic compound are CsF. This proves that the given declaration is accurate.
$2Cs + F_2 \rightarrow 2CsF$

Hence, the solution is A.

Additional Information:
Now, amongst the alkali metals, Cs is the most electropositive element because its outermost electron is more loosely bound than the outermost electron of every other alkali metals. This is due to the increase within the distance between the outermost electronic configuration and the nucleus. Hence, Cs loses its electron very easily making it the maximum electropositive element. Fluorine is the maximum electronegative because it has 5 electrons in its 2p shell. The most efficient digital configuration of the 2p orbital includes 6 electrons. To acquire the ideal electronic configuration, fluorine without difficulty accepts an electron.

Note:
Cesium fluoride is a useful base in organic chemistry, due the truth that fluoride ion is largely unreactive as a nucleophile. It is reported that CsF gives higher yields in Knoevenagel condensation reactions than KF or NaF. Removal of silicon organizations (desilylation) is a main application for CsF within the laboratory, as its anhydrous nature allows smooth formation of water-touchy intermediates. Cesium fluoride in THF or DMF can attack a huge range of organosilicon compounds to provide an organosilicon fluoride and a carbanion that could then react with electrophiles.