
What are the quantum numbers for chlorine, iron, and tin?
Answer
520.5k+ views
Hint: There are four quantum numbers to give the information about the number of electrons, chape, and angular momentum and spin of the electrons and they are principal quantum number, azimuthal quantum number, magnetic quantum number and spin quantum number.
Complete answer:
- In the question it is asked to write the quantum numbers for chlorine, iron and tin.
- The atomic numbers of chlorine, iron and tin are 17, 26 and 50.
- We have to write the electronic configuration of the given elements to write their quantum numbers.
- The electronic configuration of the chlorine is $[Ne]3{{s}^{2}}3{{p}^{5}}$ .
- Therefore the quantum numbers for chlorine are principal quantum number (n) is 3, azimuthal quantum number (l) = 1 for 3p –orbital, magnetic quantum number (m) is -1, 0 , 1 and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
- The electronic configuration of iron is $[Ar]4{{s}^{2}}3{{d}^{6}}$ .
- The quantum numbers for iron are principal quantum number (n) is 4, azimuthal quantum number (l) = 2 for 3d –orbital, magnetic quantum number (m) is -2, -1, 0 , 1, 2 and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
- The electronic configuration of tin (Sn) is $[Kr]5{{s}^{2}}4{{d}^{10}}5{{p}^{2}}$ .
- The quantum numbers for tin (Sn) are principal quantum number (n) is 5, azimuthal quantum number (l) = 1 for 5p –orbital, magnetic quantum number (m) is ‘-1, 0, 1’ and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
Note:
We should know the electronic configuration of the element to write the all four quantum numbers for an element. Without knowing the number of electrons and atomic number of an element we can write the quantum numbers for it.
Complete answer:
- In the question it is asked to write the quantum numbers for chlorine, iron and tin.
- The atomic numbers of chlorine, iron and tin are 17, 26 and 50.
- We have to write the electronic configuration of the given elements to write their quantum numbers.
- The electronic configuration of the chlorine is $[Ne]3{{s}^{2}}3{{p}^{5}}$ .
- Therefore the quantum numbers for chlorine are principal quantum number (n) is 3, azimuthal quantum number (l) = 1 for 3p –orbital, magnetic quantum number (m) is -1, 0 , 1 and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
- The electronic configuration of iron is $[Ar]4{{s}^{2}}3{{d}^{6}}$ .
- The quantum numbers for iron are principal quantum number (n) is 4, azimuthal quantum number (l) = 2 for 3d –orbital, magnetic quantum number (m) is -2, -1, 0 , 1, 2 and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
- The electronic configuration of tin (Sn) is $[Kr]5{{s}^{2}}4{{d}^{10}}5{{p}^{2}}$ .
- The quantum numbers for tin (Sn) are principal quantum number (n) is 5, azimuthal quantum number (l) = 1 for 5p –orbital, magnetic quantum number (m) is ‘-1, 0, 1’ and spin quantum (s) number is either $-\dfrac{1}{2}or+\dfrac{1}{2}$ .
Note:
We should know the electronic configuration of the element to write the all four quantum numbers for an element. Without knowing the number of electrons and atomic number of an element we can write the quantum numbers for it.
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