Question

What are the products? What is the nature of the salt?
$C{H_3}COOH + NaOH \to X + Y$
A.Sodium acetate, water, acidic
B.Sodium sulphate, water, acidic
C.Sodium acetate, hydrogen, basic
D.Sodium acetate, water, basic

Answer 1

Hint: The acetic acid found in the vinegar will react with NaOH until all of the acetic acid is neutralized. When an acid, such as acetic acid reacts with a base like NaOH, the products were salt and water.

Complete answer:
Acetic acid will react with sodium hydroxide to produce sodium acetate and water.
The unbalanced chemical equation that describes that this neutralization reaction looks like this:
$C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O$
Now, we could check to see if this chemical equation is balanced by the number of toms each element presents on both sides of the equation, or we could check by using the fact that sodium hydroxide is a strong base.
This implies that sodium hydroxide dissociates completely in aqueous solution and produces sodium cations and hydroxide anions.
$NaOH \to N{a^ + } + O{H^ - }$
Sodium acetate is soluble in aqueous solution, so it will also exist as ions.
$C{H_3}COOH + N{a^ + } + O{H^ - } \to C{H_3}CO{O^ - } + N{a^ + } + {H_2}O$
The sodium cations are spectator ions because they exist as ions on the both sides of the equation.
$C{H_3}COOH + O{H^ - } \to C{H_3}CO{O^ - } + {H_2}O$
The balance equation is:
$C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O$

Here, option (D) is the correct answer.

Note: Here we noticed that the reactant’s side has an undissociated acetate anion and the product’s side has a dissociated acetate anion, so nothing to balance out here. Similarly, the reactant's side has an undissociated proton and a dissociated hydroxide anion and the product’s side has a water molecule, so once again, there’s nothing to balance out there.