Question

What are the products of the following reaction:
 $ C{H_3} - C\left( {C{H_3}} \right) = CH - C{H_3} + HCl + {H_2}{O_2} $ ? Is it anti markovnikov?

Answer 1

Hint: Alkenes are the unsaturated hydrocarbons consisting of one or more double bonds between carbon and carbon atoms. The addition of alkenes in presence of peroxide takes place according to anti markovnikov rule which states that the negative part of the reagent attacks on the double bonded carbon consisting of a greater number of carbon atoms.

Complete answer:
Hydrocarbons are the chemical compounds consisting of only carbon and hydrogen atoms. Alkenes are the unsaturated hydrocarbons with the general molecular formula of $ {C_n}{H_{2n}} $ , where n is the number of carbon atoms.
When a reagent like hydrochloric acid is added to an alkene, it can take place in two ways. One way is according to the markovnikov rule and the other is anti markovnikov rule in presence of peroxides.
In the given reaction, alkenes are added with hydrochloric acid, and hydrogen peroxide. The reaction takes place according to markovnikov rule which states that the negative part of the reagent attacks on the double bonded carbon consisting of a greater number of carbon atoms and positive part of the reagent attacks on the double bonded carbon consisting of a smaller number of carbon atoms.
The chemical reaction can be written as:
 $ C{H_3} - C\left( {C{H_3}} \right) = CH - C{H_3} + HCl + {H_2}{O_2} \to C{H_3} - CH\left( {C{H_3}} \right) - CH\left( {Cl} \right) - C{H_3} $
Thus, the products are $ 2 $ - chloro $ 3 $ - methyl butane.

Note:
In the absence of peroxides, the addition of alkenes takes place according to the Markovnikov rule which is opposite to the Markovnikov rule. Thus, when the addition of alkenes is written. The presence of peroxide or not should be observed and the products should obey these two rules.