Question

What are the grams in $1.26 \times {10^{ - 4}}$ $mol$ of \[H{C_2}{H_3}{O_2}\] ?

Answer 1

Hint: Acetic acid, also known as ethanoic acid in the scientific community, is a colourless liquid organic compound. Acetic acid has the molecular formula as \[C{H_3}COOH\]. Vinegar contains a minimum of $4\% $ acetic acid by volume, causing acetic acid to be the primary ingredient of vinegar other than water.

Complete answer:
A chemical compound's molar mass is defined as the mass of a sample of that substance divided by the volume of material in that sample, expressed in moles. That is the density of one mole of atoms, or $6.022 \times {10^{23}}$ atoms in grams. The molar mass of a material is a bulk property.
 A mole is the mass of a sample that contains $6.022 \times {10^{23}}$ particles of that material.
The mass of a substance is the total of the average atomic masses of each atom in the chemical formula and is calculated in atomic mass units.
The formula to find the Molar mass is:
\[M = \dfrac{m}{n}\]
Here,
$M$ is the molar mass,
$m$ is the mass of a substance expressed in grams,
$n$ is the number of moles of a material.
According to the question,
$n = 1.26 \times {10^{ - 4}}$ mol
We know that the molar mass of acetic acid is $60.05g$ / $mol$.
So, $M = 60.05g$ / $mol$.
We need to find the value of $m$ .
By simplifying we can get,
$m = M \times n$
$ \Rightarrow m = 0.000126 \times 60.05$
$ \Rightarrow m = 0.00757$
Thus, the grams in $1.26 \times {10^{ - 4}}$ $mol$ of \[H{C_2}{H_3}{O_2}\] is $0.00757$ .

Note:
It must be noted that the mole is a measuring unit that is equal to the pair, dozen, gross, and so on. It determines the exact number of atoms or molecules in a bulk sample of matter. The SI unit for calculating the quantity of a material is the mole.