
What are the direction cosines of the joins of the following pairs of points (3, -4, 7), (0, 2, 5)
A). \[\dfrac{3}{7},\dfrac{{ - 6}}{7},\dfrac{2}{7}\]
B). \[\dfrac{3}{7},\dfrac{6}{7},\dfrac{{ - 2}}{7}\]
C). \[\dfrac{{ - 3}}{7},\dfrac{{ - 6}}{7},\dfrac{{ - 2}}{7}\]
D). \[\dfrac{3}{7},\dfrac{6}{7},\dfrac{2}{7}\]
Answer
504k+ views
Hint: First we will find the direction ratios. Direction ratio is the difference between the two coordinates of each coefficient. Then, we will find the direction cosines using its formula.
Complete step-by-step solution:
We will let the points from first pair as ${x_1} = 3,{y_1} = - 4,{z_1} = 7$ and from second pair as ${x_2} = 0,{y_2} = 2,{z_2} = 5$.
Now, we will find the direction ratios of the points. Direction ratios of the points are the difference of the two coordinates of each coefficient.
We will assume the first direction ratio as ‘a’.
$a = {x_1} - {x_2}$
Substituting the values in the equation.
$a = 3 - 0$
$a = 3$
We will assume the second direction ratio as ‘b’.
$b = {y_1} - {y_2}$
Substituting the values in the equation.
$b = ( - 4) - 2$
$b = - 6$
We will assume the third direction ratio as ‘c’.
$c = {z_1} - {z_2}$
Substituting the values in the equation:
$c = 7 - 5$
$c = 2$
Now, we will find the value of direction cosines. The formula of finding direction cosines is: $\dfrac{a}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{b}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{c}{{\sqrt {{a^2} + {b^2} + {c^2}} }}$. Here, a, b and c are the direction ratios.
Substituting the values in the formula
$\dfrac{3}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }},\dfrac{{ - 6}}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }},\dfrac{2}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }}$
$\dfrac{3}{{\sqrt {9 + 36 + 4} }},\dfrac{{ - 6}}{{\sqrt {9 + 36 + 4} }},\dfrac{2}{{\sqrt {9 + 36 + 4} }}$
$\dfrac{3}{{\sqrt {49} }},\dfrac{{ - 6}}{{\sqrt {49} }},\dfrac{2}{{\sqrt {49} }}$
Value of $\sqrt {49} $is 7. So, substituting it in the above equation.
$\dfrac{3}{7},\dfrac{{ - 6}}{7},\dfrac{2}{7}$
The value of direction cosines is $\dfrac{3}{7},\dfrac{{ - 6}}{7},\dfrac{2}{7}$.
So, option (A) is the correct answer.
Note: In these types of questions where 2 points are given, we have to find the direction ratios separately. If only one point will be given in the question, then, we will assume those points to be the direction ratios. And solve the questions accordingly using the same formulas as above.
Complete step-by-step solution:
We will let the points from first pair as ${x_1} = 3,{y_1} = - 4,{z_1} = 7$ and from second pair as ${x_2} = 0,{y_2} = 2,{z_2} = 5$.
Now, we will find the direction ratios of the points. Direction ratios of the points are the difference of the two coordinates of each coefficient.
We will assume the first direction ratio as ‘a’.
$a = {x_1} - {x_2}$
Substituting the values in the equation.
$a = 3 - 0$
$a = 3$
We will assume the second direction ratio as ‘b’.
$b = {y_1} - {y_2}$
Substituting the values in the equation.
$b = ( - 4) - 2$
$b = - 6$
We will assume the third direction ratio as ‘c’.
$c = {z_1} - {z_2}$
Substituting the values in the equation:
$c = 7 - 5$
$c = 2$
Now, we will find the value of direction cosines. The formula of finding direction cosines is: $\dfrac{a}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{b}{{\sqrt {{a^2} + {b^2} + {c^2}} }},\dfrac{c}{{\sqrt {{a^2} + {b^2} + {c^2}} }}$. Here, a, b and c are the direction ratios.
Substituting the values in the formula
$\dfrac{3}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }},\dfrac{{ - 6}}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }},\dfrac{2}{{\sqrt {{3^2} + {{( - 6)}^2} + {2^2}} }}$
$\dfrac{3}{{\sqrt {9 + 36 + 4} }},\dfrac{{ - 6}}{{\sqrt {9 + 36 + 4} }},\dfrac{2}{{\sqrt {9 + 36 + 4} }}$
$\dfrac{3}{{\sqrt {49} }},\dfrac{{ - 6}}{{\sqrt {49} }},\dfrac{2}{{\sqrt {49} }}$
Value of $\sqrt {49} $is 7. So, substituting it in the above equation.
$\dfrac{3}{7},\dfrac{{ - 6}}{7},\dfrac{2}{7}$
The value of direction cosines is $\dfrac{3}{7},\dfrac{{ - 6}}{7},\dfrac{2}{7}$.
So, option (A) is the correct answer.
Note: In these types of questions where 2 points are given, we have to find the direction ratios separately. If only one point will be given in the question, then, we will assume those points to be the direction ratios. And solve the questions accordingly using the same formulas as above.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

