Question

Anshul moves towards East a distance of 5m, then he returns to his left and walks 20 meters, then again he returns left and walks 15 meters. Now he turns 45 degrees towards his right and goes straight to cover twenty root two metres. How far is he from the starting point?
A.40m
B.3m
C.50m
D.55m

Answer 1

Hint: The given question is to solve by analyzing the statement written in the question, here we have to just follow the direction using in the question and make the figure accordingly, and then calculate the distance as per asked in the question, by adding the total distance covered by the man anshul.

Complete step-by-step answer:
Here to solve this question we need to know the direction, that is north, south, east and west, as we know that north direction is in upper of the page then south will be on the down of the page and east will be on right side whereas west be on left side, now knowing this we will plot the figure for the distance covered by anshul, on solving we get:
Here we get the plot that is covered by anshul, now on solving we get:

Final point where anshul reach:
\[
   \Rightarrow dis\tan ce\,AC\,equals \\
   \Rightarrow \sin 45 = \dfrac{{AC}}{{AB}} \\
   \Rightarrow \dfrac{1}{{\sqrt 2 }} = \dfrac{{AC}}{{AB}} \\
   \Rightarrow AC = \dfrac{{20\sqrt 2 }}{{\sqrt 2 }} = 20 \;
 \]
Total distance between starting and end position equals:
\[ \Rightarrow OA(total\,length) = OC + AC = 20 + 20 = 40m\]
So, the correct answer is “Option A”.

Note: Here we need to solve the displacement done by the anshul, and in order to solve it we need to draw the path covered by the anshul, without path we cannot see the displacement and thus solve further.