Question

Anmol has a chart paper of measure $ 90cm \times 40cm, $ whereas Abhishek has one which measures $ 50cm \times 70cm. $ Which will cover more area on the table and by how much?

Answer 1

Hint: Here first of all we will use the formula to find the area of the rectangular shaped chart paper for both the Anmol and the Abhishek and will observe who’s chart paper have covered more area on the table and will take difference to know how much more area covered.

Complete step-by-step answer:
Area of the rectangular chart paper is the product of the measures of both the sides.
Area for the Anmol’s chart paper, $ {A_1} = 90 \times 40 $
Simplify the above expression finding the product of the terms on the right hand side of the equation.
Area for the Anmol’s chart paper, $ {A_1} = 3600\;c{m^2} $ ….. (A)
Now,
Area for the Abhishek’s chart paper, $ {A_2} = 50 \times 70 $
Simplify the above expression finding the product of the terms on the right hand side of the equation.
Area for the Abhishek’s chart paper, $ {A_2} = 3500\;c{m^2} $ ….. (B)
Now, the take the difference by using the equations (A) and (B)
Difference,
 $
  d = 3600 - 3500 \\
  d = 100\;c{m^2} \;
  $
Since, Anmol’s chart paper is area is more it covers the more area of the table by $ 100\;c{m^2} $

Note: To compare any two quantities, the measures of both the terms should be in the same system of units. Here it was the same system both in centimetre square but incase if they are different first convert in the same format and then compare. Know the basic conversational relations such as metre to kilometre, metre to centimetre and vice-versa.