
Ankita obtained 60 marks out of 70 in Maths, 50 out of 60 in Science, and 40 out of 50 in English. What were her percentage marks in each of the three subjects? In which subject did she perform the best? What was her percentage mark on the whole?
Answer
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Hint: To get the percentage of each subject, we will use the expression p = $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$. With this expression we will find the percentage scored by her in each subject. Then, the subject in which she scored the highest percentage is the subject in which she performed the best. To find her percentage on the whole, we need to find the grand total by adding the maximum marks that can be scored in each subject and also find the total marks scored by her in by adding the marks scored by her in each subject. Then we will use the percentage expression again and find the percentage as a whole.
Complete step by step answer:
It is given that Ankita scored 60 out of 70 marks in Maths.
Therefore, percentage scored by her in Maths is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{60}{\text{70}}\times 100=85.71%$
Thus, she scored 85.71% in Maths.
She scored 50 out of 60 in Science.
Therefore, percentage scored by her in Science is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{50}{\text{60}}\times 100=83.33%$
Thus, she scored 83.33% in Science.
She scored 40 out of 50 in English.
Therefore, percentage scored by her in English is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{40}{50}\times 100=80%$
Thus, she scored 80% in English.
Now, as we can see, she scored the most in Maths, i.e. 85.71%. So, Ankita performed best in Maths, followed by Science in which she scored 83.33% and performed worst in English out of 3 subjects with a score of 80%.
Now, the grand total of maximum marks = sum of maximum marks in each subject.
Grand total marks = 70 + 60 + 50 = 180
And total marks scored by Ankita = sum of marks scored by her in individual subject
Total marks = 60 + 50 + 40 = 150
Total percentage scored by her is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{150}{180}\times 100=83.33%$
Thus, on the whole, she scored 83.33%
Note: We get the approximate whole percentage by finding the average of the percentages scored in individual subjects, but the result would be approximate and not accurate.
Complete step by step answer:
It is given that Ankita scored 60 out of 70 marks in Maths.
Therefore, percentage scored by her in Maths is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{60}{\text{70}}\times 100=85.71%$
Thus, she scored 85.71% in Maths.
She scored 50 out of 60 in Science.
Therefore, percentage scored by her in Science is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{50}{\text{60}}\times 100=83.33%$
Thus, she scored 83.33% in Science.
She scored 40 out of 50 in English.
Therefore, percentage scored by her in English is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{40}{50}\times 100=80%$
Thus, she scored 80% in English.
Now, as we can see, she scored the most in Maths, i.e. 85.71%. So, Ankita performed best in Maths, followed by Science in which she scored 83.33% and performed worst in English out of 3 subjects with a score of 80%.
Now, the grand total of maximum marks = sum of maximum marks in each subject.
Grand total marks = 70 + 60 + 50 = 180
And total marks scored by Ankita = sum of marks scored by her in individual subject
Total marks = 60 + 50 + 40 = 150
Total percentage scored by her is given by $\dfrac{\text{marks}\ \text{obtained}}{\text{total}\ \text{marks}}\times 100$
$\Rightarrow \dfrac{150}{180}\times 100=83.33%$
Thus, on the whole, she scored 83.33%
Note: We get the approximate whole percentage by finding the average of the percentages scored in individual subjects, but the result would be approximate and not accurate.
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