
Ankit secured 75% marks in examination, if he secured 450 marks find the maximum
marks.
Answer
569.7k+ views
Hint: In this problem, first we have to consider a variable for the maximum marks. Since he
secured 75% of the maximum marks, we need to calculate the 75% of that variable. His secured
marks are given in the question. So we need to equate his given marks with the calculated marks.
From that finally we have to calculate the value of the unknown variable which will gives us the
maximum marks.
Let the maximum marks be $x$.
It is given that Ankit secured 75% of the maximum marks.
Thus, calculating 75% of $x$. This will give his marks secured out of the maximum marks.
Secured marks$ = 75\% \;{\rm{of}}\;x$
$ = \dfrac{{75}}{{100}}x$ (1)
Given that he secured 450 marks out of the total marks.
Given secured marks$ = 450$ (2)
Equating both (1) and (2) and solving for $x$.
$\begin{array}{l}\dfrac{{75}}{{100}}x = 450\\ \Rightarrow 75x = 450 \times 100\\
\Rightarrow x = \dfrac{{45000}}{{75}}\\ \Rightarrow x = 600\end{array}$
Hence, the required maximum marks is 600.
Note: Here we have to determine the total marks in the examination. Since the secured marks
and the secured percentage out of the maximum marks are given, we can calculate the maximum marks from this data easily.
secured 75% of the maximum marks, we need to calculate the 75% of that variable. His secured
marks are given in the question. So we need to equate his given marks with the calculated marks.
From that finally we have to calculate the value of the unknown variable which will gives us the
maximum marks.
Let the maximum marks be $x$.
It is given that Ankit secured 75% of the maximum marks.
Thus, calculating 75% of $x$. This will give his marks secured out of the maximum marks.
Secured marks$ = 75\% \;{\rm{of}}\;x$
$ = \dfrac{{75}}{{100}}x$ (1)
Given that he secured 450 marks out of the total marks.
Given secured marks$ = 450$ (2)
Equating both (1) and (2) and solving for $x$.
$\begin{array}{l}\dfrac{{75}}{{100}}x = 450\\ \Rightarrow 75x = 450 \times 100\\
\Rightarrow x = \dfrac{{45000}}{{75}}\\ \Rightarrow x = 600\end{array}$
Hence, the required maximum marks is 600.
Note: Here we have to determine the total marks in the examination. Since the secured marks
and the secured percentage out of the maximum marks are given, we can calculate the maximum marks from this data easily.
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