Answer
Verified
413.4k+ views
Hint – See the clock nearest to you. Clearly the minute hand will be at 12 and hour hand will be at 5 if it is 5 o’clock. The clock is a circle and a circle has in total ${360^0}$. So the angle between the two hands will be the ratio of their place value multiplied with the total angle constrained within a circle.
Complete step-by-step answer:
As we know at 5 o’clock minute hand is on the 12 number and the hour hand is on the 5 number as shown in figure.
Now as we know that the total number of degrees in a circle is 360.
Therefore the angle formed by the minute hand and hour hand is the ratio of the place value of hour hand to the place value of the minute hand multiplied by 360 degree.
Let the angle between minute and hour hand at 5 o’clock is $\theta $ (see figure).
Therefore angle formed between minute and hour hand at 5 o’clock is
$\theta = \left( {\dfrac{5}{{12}}} \right) \times {360^0} = {150^0}$.
So this is the required value of the angle between minute and hour hand at 5 o’clock.
So this is the required answer.
Note – Such type of questions requires a diagrammatic representation to see the clearer position of the placing of the different hands at that specific time. When the seconds hand revolve a complete ${360^0}$ then the minute hand is shifted one unit clockwise and when the minute rotates complete ${360^0}$ then the hour hand shifts one unit clockwise.
Complete step-by-step answer:
As we know at 5 o’clock minute hand is on the 12 number and the hour hand is on the 5 number as shown in figure.
Now as we know that the total number of degrees in a circle is 360.
Therefore the angle formed by the minute hand and hour hand is the ratio of the place value of hour hand to the place value of the minute hand multiplied by 360 degree.
Let the angle between minute and hour hand at 5 o’clock is $\theta $ (see figure).
Therefore angle formed between minute and hour hand at 5 o’clock is
$\theta = \left( {\dfrac{5}{{12}}} \right) \times {360^0} = {150^0}$.
So this is the required value of the angle between minute and hour hand at 5 o’clock.
So this is the required answer.
Note – Such type of questions requires a diagrammatic representation to see the clearer position of the placing of the different hands at that specific time. When the seconds hand revolve a complete ${360^0}$ then the minute hand is shifted one unit clockwise and when the minute rotates complete ${360^0}$ then the hour hand shifts one unit clockwise.
Recently Updated Pages
The branch of science which deals with nature and natural class 10 physics CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Define absolute refractive index of a medium
Find out what do the algal bloom and redtides sign class 10 biology CBSE
Prove that the function fleft x right xn is continuous class 12 maths CBSE
Find the values of other five trigonometric functions class 10 maths CBSE
Trending doubts
How do you solve x2 11x + 28 0 using the quadratic class 10 maths CBSE
Which type of bond is stronger ionic or covalent class 12 chemistry CBSE
What organs are located on the left side of your body class 11 biology CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
How fast is 60 miles per hour in kilometres per ho class 10 maths CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
When people say No pun intended what does that mea class 8 english CBSE