
An item was sold for $Rs\,540$ at a loss of $5\% $. What was its cost price?
Answer
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Hint: The given question revolves around the topic and concepts of profit and loss. The question deals with first purchasing some goods at a cost price, then selling the goods at a selling price incurring a loss of $5\% $ in the transaction. So, we will first consider the cost price to be x and then find the loss incurred by finding $5\% $ of the cost price of the item. Then, we will find the selling price of the item in terms of variable x and equate it to the given amount.
Complete step by step answer:
So, let us assume the cost price of the item be Rs x.
Now, we have the loss percent as $5\% $.
So, we calculate the loss percent by calculating $5\% $ of the cost price.
So, $5\% $ of x is $\dfrac{5}{{100}} \times \left( {Rs\,x} \right)$.
We cancel the common factors in numerator and denominator.
Hence, the loss incurred in the transaction is $Rs\,\dfrac{x}{{20}}$.
Now, since we have incurred a loss in the whole transaction. So, we have the formula ${\text{Selling Price = }}\left( {{\text{Cost}}{\text{Price}}} \right) - \left( {{\text{Loss}}} \right)$
So, we get the selling price as ${\text{Selling Price = }}\left( {\text{x}} \right) - \left( {\dfrac{x}{{20}}} \right)$
Taking LCM and simplifying the expression, we get,
$ \Rightarrow {\text{Selling Price = }}\left( {\dfrac{{20x - x}}{{20}}} \right)$
$ \Rightarrow {\text{Selling Price = }}\left( {\dfrac{{19x}}{{20}}} \right)$
Now, we are given the selling price of the item as $Rs\,540$. Equating both, we get,
$\left( {\dfrac{{19x}}{{20}}} \right) = 540$
Using the rule of transposition and shifting the terms in the equation, we get,
$ \Rightarrow x = 540 \times \dfrac{{20}}{{19}}$
Simplifying the calculations, we get,
$ \Rightarrow x = \dfrac{{10800}}{{19}}$
$ \Rightarrow x = 568.42$
Hence, the cost price of the item is $Rs\,568.42$
Note:
One must have accuracy in arithmetic so as to solve these types of questions within a limited time frame. We should have a clear understanding of how to find the percentage of a specific number so as to find the gain and loss percent for the goods. We must know the formula to calculate the selling price when provided with cost price and loss incurred.
Complete step by step answer:
So, let us assume the cost price of the item be Rs x.
Now, we have the loss percent as $5\% $.
So, we calculate the loss percent by calculating $5\% $ of the cost price.
So, $5\% $ of x is $\dfrac{5}{{100}} \times \left( {Rs\,x} \right)$.
We cancel the common factors in numerator and denominator.
Hence, the loss incurred in the transaction is $Rs\,\dfrac{x}{{20}}$.
Now, since we have incurred a loss in the whole transaction. So, we have the formula ${\text{Selling Price = }}\left( {{\text{Cost}}{\text{Price}}} \right) - \left( {{\text{Loss}}} \right)$
So, we get the selling price as ${\text{Selling Price = }}\left( {\text{x}} \right) - \left( {\dfrac{x}{{20}}} \right)$
Taking LCM and simplifying the expression, we get,
$ \Rightarrow {\text{Selling Price = }}\left( {\dfrac{{20x - x}}{{20}}} \right)$
$ \Rightarrow {\text{Selling Price = }}\left( {\dfrac{{19x}}{{20}}} \right)$
Now, we are given the selling price of the item as $Rs\,540$. Equating both, we get,
$\left( {\dfrac{{19x}}{{20}}} \right) = 540$
Using the rule of transposition and shifting the terms in the equation, we get,
$ \Rightarrow x = 540 \times \dfrac{{20}}{{19}}$
Simplifying the calculations, we get,
$ \Rightarrow x = \dfrac{{10800}}{{19}}$
$ \Rightarrow x = 568.42$
Hence, the cost price of the item is $Rs\,568.42$
Note:
One must have accuracy in arithmetic so as to solve these types of questions within a limited time frame. We should have a clear understanding of how to find the percentage of a specific number so as to find the gain and loss percent for the goods. We must know the formula to calculate the selling price when provided with cost price and loss incurred.
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