
An instructor has a question bank consisting of 300 easy True/False questions, 200 difficult True/False questions, 500 easy multiple-choice questions, and 400 difficult multiple-choice questions. If a question is selected at random from the question bank, what is the probability that it will be an easy question given that it is a multiple-choice question?
Answer
581.1k+ views
Hint: In this question, first of all, draw a tabular form to write and understand the given data simply. Then calculate the probability of selecting an easy multiple-choice question and use conditional probability to get the required probability. So, use this concept to reach the solution to the given problem.
Let us define the following events as:
\[E\]: gets an easy question
\[M\]: gets a multiple-choice question
\[D\]: gets a difficult question
\[T\]: gets a True/False question
The questions in the question bank can be tabulated as follows:
So, the total number of questions = 1400
Total number of multiple-choice questions = 900
Therefore, probability of selecting an easy multiple-choice question is given by
\[P\left( {E \cap M} \right) = \dfrac{{500}}{{1400}} = \dfrac{5}{{14}}\]
And probability of selecting a multiple-choice question is given by
\[P\left( M \right) = \dfrac{{900}}{{1400}} = \dfrac{9}{{14}}\]
The probability that a randomly selected question will be an easy question, given that it is a multiple-choice question is given by
\[P\left( {E\left| M \right.} \right) = \dfrac{{P\left( {E \cap M} \right)}}{{P\left( M \right)}} = \dfrac{{\dfrac{5}{{14}}}}{{\dfrac{9}{{14}}}} = \dfrac{5}{9}\]
Thus, the required probability is \[\dfrac{5}{9}\].
Note: The probability of an event is always lying between 0 and 1 i.e., \[0 \leqslant P\left( E \right) \leqslant 1\]. We know that the probability of an event \[E\] is given by \[P\left( E \right) = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}\]. The condition probability of an event B is the probability that the event will occur given the knowledge that an event A has already occurred. This probability is written as \[P\left( {B\left| A \right.} \right)\].
Let us define the following events as:
\[E\]: gets an easy question
\[M\]: gets a multiple-choice question
\[D\]: gets a difficult question
\[T\]: gets a True/False question
The questions in the question bank can be tabulated as follows:
| True/False | Multiple choice | Total | |
| Easy | 300 | 500 | 800 |
| Difficult | 200 | 400 | 600 |
| Total | 500 | 900 | 1400 |
So, the total number of questions = 1400
Total number of multiple-choice questions = 900
Therefore, probability of selecting an easy multiple-choice question is given by
\[P\left( {E \cap M} \right) = \dfrac{{500}}{{1400}} = \dfrac{5}{{14}}\]
And probability of selecting a multiple-choice question is given by
\[P\left( M \right) = \dfrac{{900}}{{1400}} = \dfrac{9}{{14}}\]
The probability that a randomly selected question will be an easy question, given that it is a multiple-choice question is given by
\[P\left( {E\left| M \right.} \right) = \dfrac{{P\left( {E \cap M} \right)}}{{P\left( M \right)}} = \dfrac{{\dfrac{5}{{14}}}}{{\dfrac{9}{{14}}}} = \dfrac{5}{9}\]
Thus, the required probability is \[\dfrac{5}{9}\].
Note: The probability of an event is always lying between 0 and 1 i.e., \[0 \leqslant P\left( E \right) \leqslant 1\]. We know that the probability of an event \[E\] is given by \[P\left( E \right) = \dfrac{{{\text{Number of favourable outcomes}}}}{{{\text{Total number of outcomes}}}}\]. The condition probability of an event B is the probability that the event will occur given the knowledge that an event A has already occurred. This probability is written as \[P\left( {B\left| A \right.} \right)\].
Recently Updated Pages
Which cell organelles are present in white blood C class 11 biology CBSE

What is the molecular geometry of BrF4 A square planar class 11 chemistry CBSE

How can you explain that CCl4 has no dipole moment class 11 chemistry CBSE

Which will undergo SN2 reaction fastest among the following class 11 chemistry CBSE

The values of mass m for which the 100 kg block does class 11 physics CBSE

Why are voluntary muscles called striated muscles class 11 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

State the laws of reflection of light

Difference Between Prokaryotic Cells and Eukaryotic Cells

Show that total energy of a freely falling body remains class 11 physics CBSE

