
An important product in the ozone depletion by chlorofluorocarbons is:
A. $C{l_2}$
B. $OCl$
C. $O{F_2}$
D. ${O_2}{F_2}$
Answer
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Hint:Ozone is a highly reactive, inorganic, pale blue gas consisting of three oxygen atoms. It is also called trioxygen. The molecular formula of ozone is ${O_3}$. Chlorofluorocarbons are the compounds containing carbon, chlorine and fluorine. Ozone depletion by chlorofluorocarbons is the reaction of ozone with chlorofluorocarbons. So write the reaction of these compounds to get the answer.
Complete step-by-step answer:We are given to find the important product formed in the ozone depletion by chlorofluorocarbons.
Ozone is a triatomic gas. It has three oxygen atoms. It is a pale blue gas with a pungent smell. Ozone is formed by the action of Ultraviolet light on oxygen.
Chlorofluorocarbons are the compounds containing carbon, fluorine and chlorine. These are nontoxic, nonflammable chemicals. These compounds destroy the ozone layer of the Earth, which shields from the earth from harmful Ultraviolet rays.
Chlorine atoms from chlorofluorocarbons first get released from the parent compounds because of the action of ultraviolet rays on them and these released chlorine atoms react with ozone gas to form chlorine monoxide leaving an oxygen molecule.
The formula of chlorofluorocarbon is $CFC{l_3}$
One chlorine atom from $CFC{l_3}$ gets released from it because of UV radiation in the stratosphere.
$CFC{l_3}\mathop \to \limits^{UV} Cl\cdot + \cdot CFC{l_2}$
This released chlorine atom then reacts with ozone.
$Cl\cdot + {O_3} \to OCl + {O_2}$
Therefore, the important product in the ozone depletion by chlorofluorocarbons is chlorine monoxide, $OCl$.
Hence, the correct option is Option B.
Note: Ozone exists both naturally and as man-made. It is an allotrope of oxygen that is much less stable than di-atomic oxygen. Ozone layer is only present in the stratosphere. Do not confuse chlorofluorocarbons (cfcs) with hydrochlorofluorocarbons (hcfcs). These two are harmful for the ozone layer but hcfcs have less effect than cfcs.
Complete step-by-step answer:We are given to find the important product formed in the ozone depletion by chlorofluorocarbons.
Ozone is a triatomic gas. It has three oxygen atoms. It is a pale blue gas with a pungent smell. Ozone is formed by the action of Ultraviolet light on oxygen.
Chlorofluorocarbons are the compounds containing carbon, fluorine and chlorine. These are nontoxic, nonflammable chemicals. These compounds destroy the ozone layer of the Earth, which shields from the earth from harmful Ultraviolet rays.
Chlorine atoms from chlorofluorocarbons first get released from the parent compounds because of the action of ultraviolet rays on them and these released chlorine atoms react with ozone gas to form chlorine monoxide leaving an oxygen molecule.
The formula of chlorofluorocarbon is $CFC{l_3}$
One chlorine atom from $CFC{l_3}$ gets released from it because of UV radiation in the stratosphere.
$CFC{l_3}\mathop \to \limits^{UV} Cl\cdot + \cdot CFC{l_2}$
This released chlorine atom then reacts with ozone.
$Cl\cdot + {O_3} \to OCl + {O_2}$
Therefore, the important product in the ozone depletion by chlorofluorocarbons is chlorine monoxide, $OCl$.
Hence, the correct option is Option B.
Note: Ozone exists both naturally and as man-made. It is an allotrope of oxygen that is much less stable than di-atomic oxygen. Ozone layer is only present in the stratosphere. Do not confuse chlorofluorocarbons (cfcs) with hydrochlorofluorocarbons (hcfcs). These two are harmful for the ozone layer but hcfcs have less effect than cfcs.
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