Question

An electric kettle is rated \[3kW\] , \[250V\] . What is the current in the kettle and whether this kettle can be used in a current \[13A\] fuse?
A. \[13A\] , yes
B. \[12A\] , no
C. \[12A\] , yes
D. \[7.5A\] , yes

Answer 1

Hint:We start by finding the value of current associated with the given power and voltage using the formula given above. We state how the kettle works and then compare the value of the electric current we get to the fuse in the circuit. If the value of current we get is greater than the value of the fuse, the answer will be no and the fuse blows.

Formulas used:
The power of the kettle is given by the formula,
\[P = VI\]
Where \[I\] is the current associated with the kettle and \[V\] is the voltage associated with the kettle.

Complete step by step answer:
The electric power in watts related to a total electric circuit or a circuit segment addresses the rate at which energy is changed over from the electrical energy of the moving charges to some other structure, e.g., heat, mechanical energy, or energy put away in electric fields or attractive fields.

The power is given by the result of applied voltage and the electric flow. We now find the value of the current associated with the kettle using the formula,
\[P = VI\]
We substitute the values in the formula and arrive at,
\[I = \dfrac{P}{V} \\
\Rightarrow I= \dfrac{{3000\,W}}{{250\,V}} \\
\therefore I= 12\,A\]
As this value is less than the fuse limit, the current will flow through the circuit. This makes the answer \[12\,A\] and yes.

Hence, the right answer is option C.

Note:The kettle works on the principle of conservation of energy. Inside every Kettle, there is a metal coil. Electrical energy travels through the coil, turning into heat and warming the cold water inside it. The energy is neither created nor destroyed but transformed from one form to another.