Question

An electric iron of $1100\,W$ is operated for $2$ hours daily. What will be the electrical consumption expenses for that time in the month of April if the electricity company charges $Rs\,5$ per unit of energy?

Answer 1

Hint: In the given question, we are required to calculate the cost of electricity used in the month of April when an electric iron of $1100W$ is operated for $2$ hours daily and the rate of electricity charged by the company is also given. So, we have to calculate the total amount of energy consumed in a day and then multiply it by the rate of electricity to find the total cost.

Complete step by step answer:
So, we have the power of iron $ = 1100\,W$.
Converting the power into kilowatts by the conversion $1000\,W = 1\,KW$, we get,
Power of iron $ = 1.1\,KW$
Now, the time for which iron is used each day $ = 2$ hours
Now, we know that energy consumed can be calculated using the formula $Energy = \left( {Power} \right) \times \left( {Time} \right)$.
Energy consumed by iron each day $ = \left( {2 \times 1.1} \right)\,KWh = 2.2\,KWh$

Now, we know that the month of April has $30$ days.
So, the total amount of energy consumed in April $ = 30 \times 2.2\,KWh = 66\,KWh$
Now, we are given the rate of electricity as $Rs\,5$ per unit of energy.
So, the cost of electricity $ = Rs\,\left( {5 \times 66} \right)$
Doing the calculations, we get,
The cost of electricity $ = Rs\,330$
Hence, the total cost of electricity charged by the company at the rate of $Rs\,5$ per unit of energy for the time in which electric iron of $1100\,W$ is operated for $2$ hours daily is $Rs\,330$.

Note: We should remember the formula for calculating the energy consumed by the iron given the power and the time duration. We should know some simplification formula for simplifying the calculations and expressions while solving the problem. One must take care of calculations and arithmetic in such numericals to get to the required answer.