
An aqueous solution containing one gram of urea boils at ${100.25^o}C$. The aqueous solution containing 3 $g$ of glucose in the same volume will boil at:
(A) ${100^o}C$
(B) ${100.25^o}C$
(C) ${100.5^o}C$
(D) ${100.75^o}C$
Answer
532.8k+ views
Hint :A fluid solution is an answer where the dissolvable is water. It generally appeared in compound conditions by affixing (aq) to the significant synthetic equation. For instance, an answer of table salt, or sodium chloride, in water would be spoken to as
$N{a^ + }_{(aq)} + C{l^ - }_{(aq)}$.
Complete Step By Step Answer:
Solution of nonelectrolyte having the same focus will bubble at the same temperature.
10 $g$ of urea; $m = {\raise0.7ex\hbox{${\left( {{\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60}}}\right.}
\!\lower0.7ex\hbox{${60}$}}} \right)}$} \!\mathord{\left/
{\vphantom {{\left( {{\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60}}}\right.}
\!\lower0.7ex\hbox{${60}$}}} \right)} v}}\right.}
\!\lower0.7ex\hbox{$v$}}$ = ${\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60v}}}\right.}
\!\lower0.7ex\hbox{${60v}$}}$
3 $g$ of glucose; $m = {\raise0.7ex\hbox{${\left( {{\raise0.7ex\hbox{$3$} \!\mathord{\left/
{\vphantom {3 {180}}}\right.}
\!\lower0.7ex\hbox{${180}$}}} \right)}$} \!\mathord{\left/
{\vphantom {{\left( {{\raise0.7ex\hbox{$3$} \!\mathord{\left/
{\vphantom {3 {180}}}\right.}
\!\lower0.7ex\hbox{${180}$}}} \right)} v}}\right.}
\!\lower0.7ex\hbox{$v$}}$ = ${\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60v}}}\right.}
\!\lower0.7ex\hbox{${60v}$}}$
We know ,
$ \Rightarrow \Delta Tb = kb \times m$
$ \Rightarrow \Delta Tb\alpha m$
Here, molarity stays unaltered
Henceforth, they have a similar breaking point.
Subsequently, the right alternative is B.
Additional Information:
Watery solutions frequently permit directing power. Solutions that contain solid electrolytes will in general be excellent electrical transmitters, for example, seawater. Then again, solutions that contain powerless electrolytes will in general be helpless conductors, for example, faucet water. It is a result of that solid electrolytes totally separate into particles in water, while feeble electrolytes deficiently separate. At the point when synthetic responses happen between species in a fluid solution, the responses are typically double substitution responses. In such responses, the cation from one reactant has the spot for the cation in the other reactant. Thus, it is normally shaping an ionic bond. Responses in watery solution may bring about the items which are solvent in water or they may give a hasten. A hasten is a compound having low solvency and that regularly drops out of solution as a strong.
The terms corrosive, base are relevant to watery solutions.
Note :
Fluid solutions regularly permit leading power. Solutions that contain solid electrolytes will in general be awesome electrical transmitters, for example, seawater. Then again, solutions that contain feeble electrolytes will in general be helpless conductors, for example, faucet water. A substance will frame a fluid solution or not, it relies upon the idea of its compound bonds. A few instances of fluid solutions are cola, saltwater, downpour, corrosive solutions, base solutions, salt solutions, and so on
$N{a^ + }_{(aq)} + C{l^ - }_{(aq)}$.
Complete Step By Step Answer:
Solution of nonelectrolyte having the same focus will bubble at the same temperature.
10 $g$ of urea; $m = {\raise0.7ex\hbox{${\left( {{\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60}}}\right.}
\!\lower0.7ex\hbox{${60}$}}} \right)}$} \!\mathord{\left/
{\vphantom {{\left( {{\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60}}}\right.}
\!\lower0.7ex\hbox{${60}$}}} \right)} v}}\right.}
\!\lower0.7ex\hbox{$v$}}$ = ${\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60v}}}\right.}
\!\lower0.7ex\hbox{${60v}$}}$
3 $g$ of glucose; $m = {\raise0.7ex\hbox{${\left( {{\raise0.7ex\hbox{$3$} \!\mathord{\left/
{\vphantom {3 {180}}}\right.}
\!\lower0.7ex\hbox{${180}$}}} \right)}$} \!\mathord{\left/
{\vphantom {{\left( {{\raise0.7ex\hbox{$3$} \!\mathord{\left/
{\vphantom {3 {180}}}\right.}
\!\lower0.7ex\hbox{${180}$}}} \right)} v}}\right.}
\!\lower0.7ex\hbox{$v$}}$ = ${\raise0.7ex\hbox{$1$} \!\mathord{\left/
{\vphantom {1 {60v}}}\right.}
\!\lower0.7ex\hbox{${60v}$}}$
We know ,
$ \Rightarrow \Delta Tb = kb \times m$
$ \Rightarrow \Delta Tb\alpha m$
Here, molarity stays unaltered
Henceforth, they have a similar breaking point.
Subsequently, the right alternative is B.
Additional Information:
Watery solutions frequently permit directing power. Solutions that contain solid electrolytes will in general be excellent electrical transmitters, for example, seawater. Then again, solutions that contain powerless electrolytes will in general be helpless conductors, for example, faucet water. It is a result of that solid electrolytes totally separate into particles in water, while feeble electrolytes deficiently separate. At the point when synthetic responses happen between species in a fluid solution, the responses are typically double substitution responses. In such responses, the cation from one reactant has the spot for the cation in the other reactant. Thus, it is normally shaping an ionic bond. Responses in watery solution may bring about the items which are solvent in water or they may give a hasten. A hasten is a compound having low solvency and that regularly drops out of solution as a strong.
The terms corrosive, base are relevant to watery solutions.
Note :
Fluid solutions regularly permit leading power. Solutions that contain solid electrolytes will in general be awesome electrical transmitters, for example, seawater. Then again, solutions that contain feeble electrolytes will in general be helpless conductors, for example, faucet water. A substance will frame a fluid solution or not, it relies upon the idea of its compound bonds. A few instances of fluid solutions are cola, saltwater, downpour, corrosive solutions, base solutions, salt solutions, and so on
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