Question

An amount of oxalic acid present in the solution can be oxidised by its titration with $KMn{O_4}$ solution in the presence of ${H_2}S{O_4}$ . The titration gives unsatisfactory result when carried out in the presence of $HCl$ , because $HCl$ :
A. oxidises oxalic acid to carbon dioxide and water
B. gets oxidised by oxalic acid to chlorine
C. furnishes ${H^ + }$ ions in addition to those from oxalic acid
D. reduces permanganate to $M{n^{2 + }}$

Answer 1

Hint: To know the exact option, we should go through the given reaction of the question, and conclude why the titration gives unsatisfactory results when carried out in the presence of $HCl$ . We will also discuss more about the $HCl$ .

Complete step by step answer:
$HCl$ reduces $M{n^{7 + }}$ to $M{n^{2 + }}$ i.e. why ${H_2}S{O_4}$ is used instead of $HCl$ .
Hydrochloric acid (also called $HCl$ , $HCl$ acid or betaine hydrochloride in supplement form) is considered one of the most important fluids (or “juices”) found in the human body. $HCl$ is found inside the stomach and needed for many processes involved in digestive health. Unfortunately as you age, your production of hydrochloric acid decreases — which can increase gastrointestinal issues like heartburn, bloating and poor nutrient absorption. Additionally, not producing enough $HCl$ can lead to many other problems, such as skin problems, including acne or rosacea, mineral deficiencies and autoimmune reactions.
$HCl$ is a strong acid given that it has a low pH level, which helps to keep the stomach a very acidic environment. While normally we want to avoid having our bodies become overly acidic, preferring instead to remain slightly more alkaline, our stomach is an exception. The stomach should be a very acidic place (stomach acidity should remain between a pH of 1 and 2) because acid helps kill microbes and pathogenic bacteria that may be a threat to us.

So, the correct answer is Option D.

Note: $HCl$ $({H^ + })$ can be reduced to hydrogen gas via a weaker oxidizing agent than $HCl$ (stronger reducing agent) such as $Zn$ . There is no ultimate oxidizing agent or reducing agent.