Question

An acid Sulphur dioxide reacts with sodium hydroxide solution to form a salt called sodium sulphate $ N{a_2}S{O_3} $ and water. Write a balanced chemical equation for the reaction (show state symbols)?

Answer 1

Hint: Given that an acid sulphur dioxide and sodium hydroxide are reacted, when an acid and base are reacted it leads to the formation of an inorganic salt along with water. When acid sulphur dioxide and sodium hydroxide are reacted, sodium sulphite along with water is formed.

Complete answer:
Chemical compounds are classified into three types based on nature, they are acids, bases and neutral compounds. Sodium hydroxide is an example of a strong base as it can abstract the proton easily. Water is a neutral compound. Given that an acid Sulphur dioxide is reacted with sodium hydroxide solution.
The balanced chemical equation for the reaction of an acid sulphur dioxide and sodium hydroxide is
 $ S{O_{2\left( g \right)}} + 2NaO{H_{\left( {aq} \right)}} \to N{a_2}S{O_3}_{\left( s \right)} + {H_2}{O_{\left( l \right)}} $
In the balanced chemical equation, the atoms in the reactants side should be equal to the atoms in the products side.
Sulphur dioxide is a gas and sodium hydroxide is a solution means it is an aqueous, sodium sulphite is a salt formed as a precipitate and can be termed as solid, water is a liquid.

Note:
When an acidic compound and a basic compound are reacted, a neutralization reaction occurs that leads to the formation of an inorganic salt along with water. Given that sodium hydroxide solution means sodium hydroxide pellets were dissolved in water to prepare the solution. Thus, it can be termed as aqueous.