An a.c. generator consists of a coil of 10,000 turns and of area 100 $cm^2$. The coil rotates at an angular speed of 140 rpm in a uniform magnetic field of \[3.6 \times {10^{ - 2}}\;T\]. Find the maximum value of the emf induced.
Answer
613.2k+ views
Hint: We can apply the concept of Faraday’s law which basically summarizes the methods a voltage or emf can be produced via a changing magnetic environment. The induced voltage or emf in a coil is mainly equal to the negative of the rate of changing magnetic flux times the number of turns in the coil. It majorly involves the interaction of charge with the magnetic field.
Complete Step by Step Answer :
Therefore, the maximum value of the emf induced is 52.9 volts.
Note: It should be noted that the action of moving a loop or coil of wire through a magnetic field actually induces a voltage in coil having the magnitude of the induced voltage being related to or proportional to the velocity or speed of the movement.
Complete Step by Step Answer :
From Faraday’s law, the expression of induced emf in the rotating coil is:
$\varepsilon = - \dfrac{{d{\phi _m}}}{{dt}}$
And magnetic flux through the loop can be expressed as ${\phi _m} = NBA\cos \omega t$
As a result, the induced emf in the rotating coil is:
$\varepsilon = NBA\omega (\sin \omega t)$
The maximum emf is induced when $\left| {\sin \omega t} \right| = 1$
Thus, the induced emf can be expressed as:
${\varepsilon _{\max }} = NBA\omega \\$
$\text{where}{\text{ }}\omega = 2\pi f $
$N$ = number of turns, $B$ = magnetic field, $A$ = area ($m^2$), $f$ = frequency of rotation, $\omega$ = angular speed
In the question, we are provided with the following information:
$N = 10,000$
$A = 100 \,cm^2 = 0.01\,m^2$
$f = 140\,rpm = 140/60\,rps$
\[B = 3.6 \times {10^{ - 2}}\;T\]
First of all, we will calculate the value of angular speed:
$\omega = 2 \times \pi \times \dfrac{{140}}{{60}} = 14.7\,rad/s$
Now we will calculate the maximum value of induced emf by substituting all the values in emf formula:
${\varepsilon _{\max }} = 10000 \times 3.6 \times {10^{ - 2}} \times 0.01 \times 14.7 = 52.9\,volts$
Therefore, the maximum value of the emf induced is 52.9 volts.
Note: It should be noted that the action of moving a loop or coil of wire through a magnetic field actually induces a voltage in coil having the magnitude of the induced voltage being related to or proportional to the velocity or speed of the movement.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Class 10 Question and Answer - Your Ultimate Solutions Guide

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Why is the cell called the structural and functional class 12 biology CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

