Ammonia is not produced in the reaction of.
A) $N{H_4}Cl$ and $KOH$
B) $AIN$ With water
C) $N{H_4}Cl$ with $NaN{O_2}$
D) $N{H_4}Cl$ with $Ca{\left( {OH} \right)_2}$
Answer
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Hint:We know that Ammonia is a colorless, pungent gas containing nitrogen and hydrogen. It is the steady compound of these elements and acts as a starting material for the manufacture of many commercially significant nitrogen compounds.
Complete step by step answer:
To get the answer for this question let us see options mentioned and the reactions and find out whether ammonia gas is released during the reaction or not.
When $N{H_4}Cl$ and $KOH$ react together to form $KCl$,$N{H_{\text{3}}}$ and water as product. We can write the chemical equation for this reaction as,
$N{H_4}Cl + KOH \to KCl + {H_2}O + N{H_3}$
In this reaction ammonia is produced as a product. Therefore, the option A is incorrect.
When $AIN$ is treated with water which gives ammonia and $Al\left( {OH} \right){}_3$. We can write the chemical equation for this reaction as,
$AIN + 3{H_2}O\, \to N{H_3} + Al{\left( {OH} \right)_3}$
In this reaction ammonia is produced as a product. Therefore, the option B is incorrect.
When $N{H_4}Cl$ and $NaN{O_2}$ react together it forms sodium chloride, water and nitrogen. We can write the chemical equation for this reaction as, $N{H_4}Cl + NaN{O_2} \to {N_2} + 2{H_2}O + NaCl$
There is no liberation of ammonia in the above reaction.
Therefore, the option C is incorrect.
When $N{H_2}Cl$is treated with $Ca{\left( {OH} \right)_2}$which forms calcium chloride, ammonia and water. We can write the chemical equation for this reaction as,
$2N{H_4}Cl + Ca{\left( {OH} \right)_2} \to CaC{l_2} + 2N{H_3} + {H_2}O$
In the above reaction ammonia is formed as a product.
Therefore, the option D is incorrect.
Hence option B is correct.
Additional note:
We know the Haber process for the synthesis of ammonia is predicated on the reaction of nitrogen and hydrogen. The reaction is given below. Notably, during this process, the reaction is a chemical reaction one where there's a release of energy.
Composition:
The proportions of nitrogen and hydrogen: The mixture of nitrogen and hydrogen going into the reactor is within the ratio of 1 volume of nitrogen to three volumes of hydrogen. Avogadro's law says that equal volumes of gases at an equivalent temperature and pressure contain equal numbers of molecules. Meaning that the gases are entered into the reactor within the ratio of 1 molecule of nitrogen to three of hydrogen. That’s the proportion demanded by the equation.
\[{N_2}\left( g \right) + 3{H_2}\left( g \right) \to 2N{H_3}\left( g \right)\]
Note: Some uses of ammonia is listed below as:
> Production of ammonia is vital because it is one among the most components in making fertilizers.
Ammonia produced is employed in making nitro-based explosives including TNT, RDX, etc.
> It's utilized in manufacturing certain sorts of drugs like sulfonamide, antimalarials, and vitamins like thiamine and nicotinamide.
> It's also utilized in large-scale refrigeration plants, air-conditioning units in Buildings, etc.
Ammonia is employed in various cleaning products and acts as an efficient cleaning agent.
Complete step by step answer:
To get the answer for this question let us see options mentioned and the reactions and find out whether ammonia gas is released during the reaction or not.
When $N{H_4}Cl$ and $KOH$ react together to form $KCl$,$N{H_{\text{3}}}$ and water as product. We can write the chemical equation for this reaction as,
$N{H_4}Cl + KOH \to KCl + {H_2}O + N{H_3}$
In this reaction ammonia is produced as a product. Therefore, the option A is incorrect.
When $AIN$ is treated with water which gives ammonia and $Al\left( {OH} \right){}_3$. We can write the chemical equation for this reaction as,
$AIN + 3{H_2}O\, \to N{H_3} + Al{\left( {OH} \right)_3}$
In this reaction ammonia is produced as a product. Therefore, the option B is incorrect.
When $N{H_4}Cl$ and $NaN{O_2}$ react together it forms sodium chloride, water and nitrogen. We can write the chemical equation for this reaction as, $N{H_4}Cl + NaN{O_2} \to {N_2} + 2{H_2}O + NaCl$
There is no liberation of ammonia in the above reaction.
Therefore, the option C is incorrect.
When $N{H_2}Cl$is treated with $Ca{\left( {OH} \right)_2}$which forms calcium chloride, ammonia and water. We can write the chemical equation for this reaction as,
$2N{H_4}Cl + Ca{\left( {OH} \right)_2} \to CaC{l_2} + 2N{H_3} + {H_2}O$
In the above reaction ammonia is formed as a product.
Therefore, the option D is incorrect.
Hence option B is correct.
Additional note:
We know the Haber process for the synthesis of ammonia is predicated on the reaction of nitrogen and hydrogen. The reaction is given below. Notably, during this process, the reaction is a chemical reaction one where there's a release of energy.
Composition:
The proportions of nitrogen and hydrogen: The mixture of nitrogen and hydrogen going into the reactor is within the ratio of 1 volume of nitrogen to three volumes of hydrogen. Avogadro's law says that equal volumes of gases at an equivalent temperature and pressure contain equal numbers of molecules. Meaning that the gases are entered into the reactor within the ratio of 1 molecule of nitrogen to three of hydrogen. That’s the proportion demanded by the equation.
\[{N_2}\left( g \right) + 3{H_2}\left( g \right) \to 2N{H_3}\left( g \right)\]
Note: Some uses of ammonia is listed below as:
> Production of ammonia is vital because it is one among the most components in making fertilizers.
Ammonia produced is employed in making nitro-based explosives including TNT, RDX, etc.
> It's utilized in manufacturing certain sorts of drugs like sulfonamide, antimalarials, and vitamins like thiamine and nicotinamide.
> It's also utilized in large-scale refrigeration plants, air-conditioning units in Buildings, etc.
Ammonia is employed in various cleaning products and acts as an efficient cleaning agent.
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