Allyl chloride is more reactive than vinyl chloride.
A. True
B. False
Answer
649.2k+ views
Hint: For this problem, we have to study which molecules have a stronger bond between chlorine atom which is attached to the carbon atom. After which we can determine that the statement is true or not.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

