Allyl chloride is more reactive than vinyl chloride.
A. True
B. False
Answer
641.4k+ views
Hint: For this problem, we have to study which molecules have a stronger bond between chlorine atom which is attached to the carbon atom. After which we can determine that the statement is true or not.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
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