
Allyl chloride is more reactive than vinyl chloride.
A. True
B. False
Answer
573.3k+ views
Hint: For this problem, we have to study which molecules have a stronger bond between chlorine atom which is attached to the carbon atom. After which we can determine that the statement is true or not.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
Complete step by step answer:
- In the given question, we have to explain whether the given statement is true or not about the allyl chloride and vinyl chloride.
- Firstly, we should know that the molecule which has the stronger bonds will need more energy to break and hence, it will be less reactive.
- So, the molecular formula of vinyl chloride and allyl chloride will be:
$\text{C}{{\text{H}}_{2}}\text{ = CH - Cl and C}{{\text{H}}_{2}}\text{ = CH - C}{{\text{H}}_{2}}\text{ - Cl}$ respectively.
- As we can see that in vinyl chloride the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{2}}$ hybridised whereas, in allyl chloride, the chlorine atom which is attached to the carbon is $\text{s}{{\text{p}}^{3}}$ hybridised.
- Now, we can say that the percentage of the s - character in the vinyl chloride and allyl chloride will be 50% and 25% respectively.
- This means that the electronegativity of carbon atoms in vinyl chloride is stronger than the carbon present in the allyl chloride due to which the bond will be stronger in the vinyl chloride.
- Hence, due to weak bonds in allyl chloride, it will be more reactive.
So, the correct answer is “Option A”.
Note: In the given problem, the electronegativity of the element is defined as the tendency of the atom to attract the shared pair of electrons. More will be electronegativity of the atom, more strong bond will it make.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

