Question

How many alkaline could you treat with $ {H_2} $ $ Pd/C $ in order to prepare methylcyclopentane?

Answer 1

Hint : $ {H_2} $ and $ Pd/C $ will reduce alkynes to alkanes it means two hydrogen atoms get added to it . Palladium catalyses the addition of hydrogen to multiple carbon-carbon bonds. This reaction will take place twice while reducing alkynes to alkanes.

Complete Step By Step Answer:
To prepare methylcyclopentane by using $ {H_2} $ , $ Pd/C $ the required alkaline are $ 4 - $ methylcyclopent $ - 1 - $ ene, $ 1 - $ methylcyclopent $ - 1 - $ ene, methylenecyclopentane and $ 3 - $ methylcyclopent $ - 1 - $ ene.

Methylenecyclopentane

 $ 3 - $ methylcyclopent $ - 1 - $ ene.

 $ 1 - $ methylcyclopent $ - 1 - $ ene

 $ 4 - $ methylcyclopent $ - 1 - $ ene

Note :
This hydrogenation reaction catches fire very easily as it has flammable reagents and solvents as it includes palladium and carbon; they are highly flammable in nature and can ignite fire very easily. The presence of hydrogen gas adds risk of explosion.