Question

${\text{AgN}}{{\text{O}}_3}$ was added to aqueous ${\text{KCl}}$ solution gradually and the conductivity of the solution was measured. The plot of conductance ($\Lambda $) versus the volume of ${\text{AgN}}{{\text{O}}_3}$.

A.(P)
B.(Q)
C.(R)
D.(S)

Answer 1

Hint: The conductance is the measurement of the conductivity of an electrolytic solution. It directly depends on the concentration of electrolyte solution. More the concentration of electrolyte solution more is the conductance.

Complete step by step answer:
Conductivity or conductance of an electrolytic solution is the measurement of the ability of a solution to conduct electricity. The specific conductance of an electrolytic solution depends upon the concentration of electrolyte. The unit of conductivity is $S/m$ .
Basically the conductivity depends upon the nature of electrolyte. If the electrolyte is strong then it will fully dissociate into ions and if the electrolyte is weak then it will dissociate partially. The strong electrolytes will have more conductivity as compared to weak electrolytes due to complete dissociation.
We have given two electrolytes ${\text{AgN}}{{\text{O}}_3}$ and ${\text{KCl}}$.
We will start adding ${\text{AgN}}{{\text{O}}_3}$ in ${\text{KCl}}$ solution. As we pour the silver nitrate into the aqueous potassium chloride the precipitate of silver chloride starts forming so the chloride ions which were depleting are replaced by the nitrate ions so the conductivity of the solution remains constant.
Reaction:
${\text{AgN}}{{\text{O}}_3}{\text{ + KCl}} \to {\text{AgC}}{{\text{l}}_{(s)}}{\text{ + KN}}{{\text{O}}_3}$
After the end point where all the chloride ions are a part of ppt., only nitrate ions will remain along with potassium cations and on further adding of silver nitrate the concentration of ions will increase because the ppt. formation has stopped hence the conductivity of the solution will increase linearly.
Hence option (D) is correct.

Note:
During the addition of silver nitrate in aqueous potassium chloride the chloride ions form the precipitate while the nitrate ions contribute to electrolytic solution so the overall conductance of the solution remains the same till the end point.