What is the additive inverse of $\dfrac{4}{7}$
Answer
570.3k+ views
Hint: The additive inverse of a number a is the number that, when added to a , yields zero. This number is also known as the opposite and sign change. The additive inverse of a is denoted by -a.
We will add a number (x) to $\dfrac{4}{7}$ which will be equal to zero to get its additive inverse.
Complete step by step answer:
Let's add an unknown number to $\dfrac{4}{7}$ to get its additive inverse.
$x + \dfrac{4}{7} = 0$
Now move constant to right hand side, we get-
$x = - \dfrac{4}{7}$
This is a required solution.
ADDITIONAL INFORMATION
Additive inverse of Complex numbers is the combination of real numbers and imaginary numbers $A + iB$ is a complex number, where A is the real number and B is the imaginary number.
Now the additive inverse of $A + iB$ should be a value, that on adding it with a given complex number, we get a result as zero. Therefore, it will be $ - (A + iB)$
The multiplicative inverse of a number, say, N is represented by $\dfrac{1}{N}$ or ${N^{ - 1}}$ . It is also called reciprocal.
The multiplicative inverse of zero is not defined. And the multiplicative inverse of 1 is 1 itself.
EXAMPLE-
$3$ is a natural number. If we multiply $3$ by $\dfrac{1}{3}$ , the product is $1$ . Therefore, the multiplicative inverse of $3$ is $\dfrac{1}{3}$ . Similarly, the multiplicative inverse of $122$ is $\dfrac{1}{{122}}$ .
Note:
An additive inverse of a number is defined as the value, which on adding with the original number results in zero value. It is the value we add to a number to yield zero. Suppose, a is the original number, then its additive inverse will be –a. Additive inverse is also called the opposite of the number, negation of number or changed sign of original number.
We will add a number (x) to $\dfrac{4}{7}$ which will be equal to zero to get its additive inverse.
Complete step by step answer:
Let's add an unknown number to $\dfrac{4}{7}$ to get its additive inverse.
$x + \dfrac{4}{7} = 0$
Now move constant to right hand side, we get-
$x = - \dfrac{4}{7}$
This is a required solution.
ADDITIONAL INFORMATION
Additive inverse of Complex numbers is the combination of real numbers and imaginary numbers $A + iB$ is a complex number, where A is the real number and B is the imaginary number.
Now the additive inverse of $A + iB$ should be a value, that on adding it with a given complex number, we get a result as zero. Therefore, it will be $ - (A + iB)$
The multiplicative inverse of a number, say, N is represented by $\dfrac{1}{N}$ or ${N^{ - 1}}$ . It is also called reciprocal.
The multiplicative inverse of zero is not defined. And the multiplicative inverse of 1 is 1 itself.
EXAMPLE-
$3$ is a natural number. If we multiply $3$ by $\dfrac{1}{3}$ , the product is $1$ . Therefore, the multiplicative inverse of $3$ is $\dfrac{1}{3}$ . Similarly, the multiplicative inverse of $122$ is $\dfrac{1}{{122}}$ .
Note:
An additive inverse of a number is defined as the value, which on adding with the original number results in zero value. It is the value we add to a number to yield zero. Suppose, a is the original number, then its additive inverse will be –a. Additive inverse is also called the opposite of the number, negation of number or changed sign of original number.
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