
Add the following numbers and check by reversing the order of the addends:
$ 16509 + 114 $
Answer
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Hint: First add the unit’s place digits of both the numbers. The resultant digit will be the unit’s place digit of the addition. Then add the ten’s place digit of both the numbers. The result will be the ten’s place digit of the addition. Keep on doing this till all the corresponding digits are added. If the addition of any two digits is not a single digit, then carry forward the ten’s place digit of the number that came after addition to the next number of the addend.
Complete step-by-step answer:
When we add two numbers, the unit's place digit of one number is added to the unit’s place digit of the other number.
Thus, $ 9 + 4 = 13 $
Since, the answer is a two-digit number, the ten’s place digit will be carried forward to the ten’s place digit of the addends. And the unit's place digit will be left as the unit’s place digit of the addition.
Thus, the unit’s place digit of the addition is 3. And carry forward is 1.
Now, the carry forward and the ten’s place digits of both the numbers are added. i.e.
$ 1 + 0 + 1 = 2 $
This will be the ten’s place digit of the addition
Now hundreds place digits of both the numbers will be added. i.e.
$ 5 + 1 = 6 $
Hence, the hundred place digit of the addition will be 6.
Now, since, there are no more digits in the number 114. The rest of the digits of the number 16059, i.e. 16 will be written as it is in the addition.
Thus, from above explanation we get
$ \Rightarrow 16509 + 114 = 16623 $
By using the same concept explained above and reversing the order of the addends, we get
$ 114 + 16509 = 16623 $
Thus we can observe that reversing the order of the addends does not change the value of the addition.
Thus, $ 16509 + 114 = 114 + 16509 $
So, the correct answer is “ $ 16509 + 114 = 114 + 16509 $ ”.
Note: Do not forget to carry forward the ten’s place digit that comes after adding the corresponding two digits of the numbers that we need to add.
The property $ a + b = b + a $ of addition is true or any positive values of $ a $ and $ b $ . This property is called commutative law of addition.
Complete step-by-step answer:
When we add two numbers, the unit's place digit of one number is added to the unit’s place digit of the other number.
Thus, $ 9 + 4 = 13 $
Since, the answer is a two-digit number, the ten’s place digit will be carried forward to the ten’s place digit of the addends. And the unit's place digit will be left as the unit’s place digit of the addition.
Thus, the unit’s place digit of the addition is 3. And carry forward is 1.
Now, the carry forward and the ten’s place digits of both the numbers are added. i.e.
$ 1 + 0 + 1 = 2 $
This will be the ten’s place digit of the addition
Now hundreds place digits of both the numbers will be added. i.e.
$ 5 + 1 = 6 $
Hence, the hundred place digit of the addition will be 6.
Now, since, there are no more digits in the number 114. The rest of the digits of the number 16059, i.e. 16 will be written as it is in the addition.
Thus, from above explanation we get
$ \Rightarrow 16509 + 114 = 16623 $
By using the same concept explained above and reversing the order of the addends, we get
$ 114 + 16509 = 16623 $
Thus we can observe that reversing the order of the addends does not change the value of the addition.
Thus, $ 16509 + 114 = 114 + 16509 $
So, the correct answer is “ $ 16509 + 114 = 114 + 16509 $ ”.
Note: Do not forget to carry forward the ten’s place digit that comes after adding the corresponding two digits of the numbers that we need to add.
The property $ a + b = b + a $ of addition is true or any positive values of $ a $ and $ b $ . This property is called commutative law of addition.
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