
Acetone formed by following ozonolysis
A. $1 - butene$
B. $2 - butene$
C. $isobutene$
D. $butyne$
Answer
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Hint: The reaction which includes carbon and their derivatives is known as organic reaction. Ozonolysis is also an organic reaction which is used to manufacture carbonyl and nitrosamines compounds from unsaturated alkenes and alkynes and azo compounds.
Complete step by step answer:
As we all know that carbon and derivatives of carbon are known as organic compounds. And the chemical reactions which involve organic compounds as reactants and products are known as organic reactions. Mostly addition, substitution, elimination, rearrangement and redox reactions are seen in the category of organic reactions.
Ozonolysis is one of the organic chemical reactions. In the ozonolysis reaction the unsaturated organic compounds with double and triple bond takes place, the cleavage of double and triple bond takes place with the help of ozone (\[{O_3}\]). In this reaction the multiple bonds present between the carbon atoms are replaced by carbonyl groups because the reaction with ozone makes the compound oxygen rich and the same happens in the case of azo compounds, the azo compounds are converted into nitrosamines due to involvement of oxygen atoms.
Ozonolysis of $1 - butene$ is as follows:
$\underbrace {C{H_3}C{H_2}CH = C{H_2}}_{butene}\xrightarrow{{ozonolysis}}\underbrace {C{H_3}C{H_2}CHO}_{propanal} + \underbrace {HCHO}_{methanal}$
So, in this reaction propanal and methanol are formed, acetone formation doesn’t take place.
Ozonolysis $2 - butene$ is as follows:
$\underbrace {C{H_3}CH = CHC{H_3}}_{2butene}\xrightarrow{{ozonolysis}}2\underbrace {C{H_3}CHO}_{ethanal}$
So, in this reaction ethanal is formed, acetone formation doesn’t take place.
Ozonolysis of $isobutene$ is as follows:
$\underbrace {C{H_3}C(C{H_3}) = C{H_2}}_{isobutene}\xrightarrow{{ozonolysis}}\underbrace {C{H_3}COC{H_3}}_{Acetone} + \underbrace {HCHO}_{methanal}$
So, in this reaction Acetone and methanol are formed, acetone formation takes place in this reaction.
And the ozonolysis of butyne is as follows:
$C{H_3}C{H_2}C \equiv CH\xrightarrow{{ozonolysis}}C{H_3}C{H_2}COCHO$
So from the above reactions we can conclude that acetone is formed by the ozonolysis of isobutene.
So, the correct answer is Option C .
Note:
As we all know that ozone is a very reactive allotrope of oxygen so in ozonolysis the ozone does oxidative cleavage of alkenes and alkynes. The double and triple bonds in the molecule are replaced by the carbon oxygen bonds and hence the carbonyl groups are produced.
Complete step by step answer:
As we all know that carbon and derivatives of carbon are known as organic compounds. And the chemical reactions which involve organic compounds as reactants and products are known as organic reactions. Mostly addition, substitution, elimination, rearrangement and redox reactions are seen in the category of organic reactions.
Ozonolysis is one of the organic chemical reactions. In the ozonolysis reaction the unsaturated organic compounds with double and triple bond takes place, the cleavage of double and triple bond takes place with the help of ozone (\[{O_3}\]). In this reaction the multiple bonds present between the carbon atoms are replaced by carbonyl groups because the reaction with ozone makes the compound oxygen rich and the same happens in the case of azo compounds, the azo compounds are converted into nitrosamines due to involvement of oxygen atoms.
Ozonolysis of $1 - butene$ is as follows:
$\underbrace {C{H_3}C{H_2}CH = C{H_2}}_{butene}\xrightarrow{{ozonolysis}}\underbrace {C{H_3}C{H_2}CHO}_{propanal} + \underbrace {HCHO}_{methanal}$
So, in this reaction propanal and methanol are formed, acetone formation doesn’t take place.
Ozonolysis $2 - butene$ is as follows:
$\underbrace {C{H_3}CH = CHC{H_3}}_{2butene}\xrightarrow{{ozonolysis}}2\underbrace {C{H_3}CHO}_{ethanal}$
So, in this reaction ethanal is formed, acetone formation doesn’t take place.
Ozonolysis of $isobutene$ is as follows:
$\underbrace {C{H_3}C(C{H_3}) = C{H_2}}_{isobutene}\xrightarrow{{ozonolysis}}\underbrace {C{H_3}COC{H_3}}_{Acetone} + \underbrace {HCHO}_{methanal}$
So, in this reaction Acetone and methanol are formed, acetone formation takes place in this reaction.
And the ozonolysis of butyne is as follows:
$C{H_3}C{H_2}C \equiv CH\xrightarrow{{ozonolysis}}C{H_3}C{H_2}COCHO$
So from the above reactions we can conclude that acetone is formed by the ozonolysis of isobutene.
So, the correct answer is Option C .
Note:
As we all know that ozone is a very reactive allotrope of oxygen so in ozonolysis the ozone does oxidative cleavage of alkenes and alkynes. The double and triple bonds in the molecule are replaced by the carbon oxygen bonds and hence the carbonyl groups are produced.
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