Question

According to the law of independent assortment, what is the probability of getting parental characters in F2-generation, when a dihybrid test cross is done?
A. 50%
B. 25%
C. 75%
D. 100%

Answer 1

Hint: Dihybrid test crossing is an investigational cross in which researchers picked one parent from the F1 generation who is heterozygous for two characteristics and another parent who is double homozygous for both traits, resulting in distinct types of gametes that would fertilise to make new organisms.

Complete answer:
Mendel's law of independent assortment says that which are present in a specific character for a certain organism is expressed in such a manner that there is no dependency between them when they are included in the gamete.

In order to proceed for the findings, Mendel performed a dihybrid cross on a pea plant and proposed the third law of inheritance. It is known as the Law of Independent Assortment. According to this, 16 progeny are produced in the F2 generation. There are four types of phenotypes and nine types of genotypes in these progeny. Sixteen progeny display genetic recombination’s, with one homozygous dominant for both traits (RRYY), eight heterozygous dominant for round and yellow, and one homozygous recessive for both (rryy).
As a result, the gamete has genotypes that are independent of the other game. Various experiments can demonstrate this.

As a result, the right answer is 50%, which is option A.

Note: Mendel's law of independent assortment asserts that alleles from two (or more) distinct genes are sorted into gametes independently of one another. Therefore in other words, the allele which a gamete receives for one gene has no effect on the allele obtained for something else.